Answer:
a. active volcanoes river valleys feeding into surface lakes of liquid water surfaces with very few impact.
Explanation:
Answer:
1.424 μC
Explanation:
I'm assuming here, that the charged ball is suspended by the string. If the string also is deflected by the angle α, then the forces acting on it would be: mg (acting downwards),
tension T (acting along the string - to the pivot point), and
F (electric force – acting along the line connecting the charges).
We then have something like this
x: T•sin α = F,
y: T•cosα = mg.
Dividing the first one by the second one we have
T•sin α/ T•cosα = F/mg, ultimately,
tan α = F/mg.
Since we already know that
q1=q2=q, and
r=2•L•sinα,
k=9•10^9 N•m²/C²
Remember,
F =k•q1•q2/r², if we substitute for r, we have
F = k•q²/(2•L•sinα)².
tan α = F/mg =
= k•q²/(2•L•sinα)² •mg.
q = (2•L•sinα) • √(m•g•tanα/k)=
=(2•0.5•0.486) • √(0.0142•9.8•0.557/9•10^9) =
q = 0.486 • √(8.61•10^-12)
q = 0.486 • 2.93•10^-6
q = 1.424•10^-6 C
q = 1.424 μC.
This question is incomplete. The complete question is given below:
Question 3 Both the angle and the magnitude of the force have a certain uncertainty: εF = 28 N and εθ = 0.8°. Using the propagation methods described in the video you watched at the beginning of this prelab, calculate the corresponding propagated uncertainty for Fx, in N. For this question, round up your final answer to two significant figures. Do not include the ± sign in your answer. Example: If the x component of F is 200±14 N, you should enter “14”.
Both the force and the angle are measured, and the results are quoted as a central value plus/minus an uncertainty:
F = F0 ± εF
θ = θ0 ± εθ
We would like to evaluate the component of the force in the x direction.
Question 2
Let us first concentrate on the central value. Take F0 = 325 N and θ0 = 57°.
The answer & explanation for this question is given in the attachment below.
1. <span> Fp = Mg*sin24 = 0.407Mg. </span>
<span>Fn = Mg*Cos24 = 0.914Mg. </span>
<span>Fk = u*0.914Mg. </span>
<span>Fp-Fk = M*a. </span>
<span>0.407Mg-u*0.914Mg = M*a.
</span>Divide by Mg:
<span>0.407-0.914u = a/g = 3.1/-9.81, </span>
<span>0.407-.914u = -0.316, uk = 0.791.
</span>
2. <span> M*g = 1200*9.8 = 11,760 N. = Wt. of car. = Normal force(Fn). </span>
<span>Fp = Mg*sin 0 = 0. </span>
<span>Fk = uk*Fn = 0.1323*11,760 = 1556 N. </span>
<span>Fp-Fk = M*a. </span>
<span>0-1556 = 1200a, a = -1.30 m/s^2. </span>
<span>V^2 = Vo^2 + 2a*d. </span>
<span>0 = (20.1)^2 - 19.6d
</span>
Answer:
According to Wien’s Law:
where;
is the wavelength
T(K) is the temperature in Kelvin
Putting the values given in the above equation:
<u><em>T(K) = 0.966×</em></u>