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EleoNora [17]
3 years ago
6

Please help me please help​

Physics
1 answer:
natita [175]3 years ago
8 0

Answer:

<u>Answer</u><u> </u><u>→</u><u> </u><u>Distance</u><u> </u><u>is</u><u> </u><u>5</u><u> </u><u>×</u><u> </u><u>1</u><u>0</u><u>⁴</u><u> </u><u>km</u><u> </u>

Explanation:

Gravitational formular

{ \tt{F =  \frac{GMm}{ {r}^{2} } }} \\

  • F is the gravitational force
  • G is the universal gravitational constant
  • r is the separation distance
  • M & m are the masses

For the first case;

{ \tt{F _{1} =  \frac{GMm}{2.5 \times  {10}^{4} }  }} \\

For the second case;

{ \tt{F _{2} =  \frac{GMm}{r _{2}}  }} \\

but F2 = ½F1

Therefore, F1 = 2F2

Hence:

{ \tt{ \frac{GMm}{2.5 \times  {10}^{4} } =2 \times   \frac{GMm}{r _{2} }  }} \\  \\ { \tt{ \frac{1}{2.5 \times  {10}^{4} }  =  \frac{2}{r _{2} }  }} \\  \\ { \tt{r _{2} = 2 \times 2.5 \times  {10}^{4} }} \\  \\ { \underline{ \tt{ \:  \: r _{2} = 5 \times  {10}^{4}   \: km \:  \: }}}

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