The question states: two large, parallel conducting plates are 12cm
1 answer:
Answer:
1. 24375 N/C
2. 2925 V
Explanation:
d = 12 cm = 0.12 m
F = 3.9 x 10^-15 N
q = 1.6 x 10^-19 C
1. The relation between the electric field and the charge is given by
F = q E
So,
E = 24375 N/C
2. The potential difference and the electric field is related by the given relation.
V = E x d
where, V be the potential difference, E be the electric field strength and d be the distance between the electrodes.
By substituting the values, we get
V = 24375 x 0.12 = 2925 Volt
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Answer:
Mechanical energy, U = 0.247 Joules
Explanation:
Given that,
Spring constant of the spring, k = 234 N/m
Mass, m = 524 g = 0.524 kg
Amplitude, A = 4.6 cm = 0.046 m
To find,
The mechanical energy of the system.
Solution,
We know that the sum of kinetic energy and the potential energy is equal to its mechanical energy. In mass-spring system, it is given by :
U = 0.247 Joules
So, the mechanical energy of the system is 0.247 Joules.