The question states: two large, parallel conducting plates are 12cm
1 answer:
Answer:
1. 24375 N/C
2. 2925 V
Explanation:
d = 12 cm = 0.12 m
F = 3.9 x 10^-15 N
q = 1.6 x 10^-19 C
1. The relation between the electric field and the charge is given by
F = q E
So,
E = 24375 N/C
2. The potential difference and the electric field is related by the given relation.
V = E x d
where, V be the potential difference, E be the electric field strength and d be the distance between the electrodes.
By substituting the values, we get
V = 24375 x 0.12 = 2925 Volt
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Explanation:
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That is: there are wave cycles in
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wave cycles will go through that point in the same amount of time. Hence, the frequency of this wave would be
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The calculations above can be expressed with the formula:
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where
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represents the wavelength of this wave.