The activity of the sample when it was shipped from the manufacturer is 4.54 mCi
<h3>How to determine the number of half-lives that has elapsed </h3>
From the question given above, the following data were obtained:
- Time (t) = 48 hours
- Half-life (t½) = 14.28 days = 14.28 × 24 = 342.72 hours
- Number of half-lives (n) =?
n = t / t½
n = 48 / 342.72
n = 0.14
<h3>How to determine the activity of the sample during shipping </h3>
- Number of half-lives (n) = 0.14
- Original activity (N₀) = 5.0 mCi
- Activity remaining (N) =?
N = N₀ / 2ⁿ
N = 5 / 2^0.14
N = 4.54 mCi
Thus, the activity of the sample during shipping is 4.54 mCi
Learn more about half life:
brainly.com/question/2674699
Answer:
Option B. 10
Explanation:
If 1 mol of butanol contains 6×10²⁴ atoms of H, let's calculate the amount of H.
(number of atoms / NA)
6.02 x 10²³ atoms ___ 1 mol
6×10²⁴ atoms will occupy (6×10²⁴ / NA) = 9.96 moles
H, has 10 moles in the butano formula.
Answer:
C₆H₁₀NO
Explanation:
In order to arrive at a molecular formula we have to make some assumptions and they are
Assuming there is one ( 1 ) N and one ( 1 ) O that is present in the said molecule
Total mass = 29.998
next step: subtract the total mass from 112.0499 = 82.501
next : assume the presence of 6 carbon atoms in said molecule
Total mass = 6 * 12 = 72
Mass of Hydrogens = 82.501 - 72 = 10.501
∴ number of hydrogens = 10.501 / 1.0078 ≈ 10
Hence Total mass = 29.998 + 82.501 ≈ 112.0499
Finally Molecular formula = C₆H₁₀NO
<span>subshells have two reasons of stability-
</span><span> 1) half filled and full filled subshells lead to symmetry as symmetry always increases stability in the nature.
</span>2)<span> in half filled and full filled subshells there are maximum no Of exchanges so exchanges releases energy so it increase stability.. Exchange of e-s also can b understood as delocalization of e-s which is similar like resonance and resonance always increases stability</span>
