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aivan3 [116]
3 years ago
15

When a radioactive isotope releases an alpha particle, the atomic number of the atom is

Chemistry
1 answer:
Ipatiy [6.2K]3 years ago
5 0
The radioactive isotope's atomic number decreases by two, and the alpha particle has an atomic number of 2. It wasnt clear which one you were asking for, so there is both.

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using the aufbau principle,write the electronic configuration for the ground state of the atom having atomic number 1 to 30​
Elina [12.6K]

Aufbau principle:

Electrons are added one at a time from the lowest energy orbitals available until all the orbitals are filled.

According to the Aufbau principle, electrons fill lower energy orbitals first.

(i) Boron (Z = 5)

Electronic configuration =  

(ii) Neon (Z = 10)  

Electronic configuration =  

(iii) Aluminium (Z = 13)  

Electronic configuration =  

(iv) Chlorine (Z = 17)

Electronic configuration =  

(v) Calcium (Z = 20)  

Electronic configuration =

[Image]

8 0
3 years ago
Express in scientific notation. Make sure your answer has the same number of significant figures as the starting value. (6.0 x 1
Greeley [361]
I believe the correct answer from the choices listed above is the second option. The expression (6.0 x 104) (3.1 x 10-1) is equal to 1.9 x 10^4. We only have two significant figures from the starting expression that is why we rounded of the product from 1.86 to 1.9.
3 0
3 years ago
VERY URGENT<br><br> which vserp shape has the longest distance?
Mumz [18]

Answer:

The bond angle in H2O is about (104.5∘). In H2O,O-atom has two lone pairs.

Explanation:

The VSEPR theory describes five main shapes of simple molecules: linear, trigonal planar, tetrahedral, trigonal bipyramidal, and octahedral.

6 0
3 years ago
What do these two changes have in common? Shaking up salad dressing. Adding dish soap to water in a sink
Ghella [55]
I think it’s a maybe hope this helps
4 0
3 years ago
A 52 gram sample of an unknown metal requires 714 Joules of energy to heat it from
ratelena [41]

Answer:  Approximately 0.267 \frac{\text{J}}{\text{g}^{\circ}\text{C}}

===================================================

Work Shown:

We have the following variables

  • Q = 714 joules = heat required
  • m = 52 grams = mass
  • c = specific heat = unknown
  • \Delta t = 82-30.5 = 51.5 = change in temperature

note: the symbol \Delta is the uppercase Greek letter delta. It represents the difference or change in a value.

Apply those values into the formula below. Solve for c.

Q = m*c*\Delta t\\\\714 = 52*c*51.5\\\\714 = 52*51.5*c\\\\714 = 2678*c\\\\2678*c = 714\\\\c = \frac{714}{2678}\\\\c \approx 0.26661687826737\\\\c \approx 0.267\\\\

The specific heat of the unknown metal is roughly 0.267 \frac{\text{J}}{\text{g}^{\circ}\text{C}}

3 0
3 years ago
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