Answer:
The outer circle is 16 feet larger than the inner circle (68 - 52).
Step-by-step explanation:
Given that the inner circle circumference is 52 feet, and the distance between the inner and the outer circle is 8 feet, to determine by how many ft is the larger outer circle, the following calculation must be performed:
The radius of a circle is equal to half its diameter. Therefore, the radius of the inner circle is 26 feet. Thus, if the distance between the two circles is 8 feet, the radius of the outer circle is 34 feet (26 + 8). Therefore, the diameter of this circle is 68 feet (34 x 2).
This implies that the outer circle is 16 feet larger than the inner circle (68 - 52).
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Answer:
-q^2 -q + 72
Step-by-step explanation:
(9+ q)(8-q)
=9(8-q)+ q(8-q)
=72 - 9q +8q -q^2
= -q^2 -q + 72
Answer:
3.75
Step-by-step explanation:
g(x)=60(1-0.5)^x, g(4)
g(4)=60(1-0.5)^4
g(4)=60(.5)^4
g(4)=60(0.0625)
g(4)=3.75
Answer:
Step-by-step explanation:
In this question, we have to find the slope with the given coordinates.
To find our slope, we would use the slope formula: 
Plug in your coordinates and solve:
Simplify the fraction:
The slope would be
