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2 years ago

An equilateral triangle has a height of 32. Find the length of the sides of the triangle. Round to the nearest hundredth.

Mathematics

1 answer:

telo118 [61]2 years ago

5 0

Let each side=x
Use pythagorus
As height at mid of other side
Then: 32=sqrt(X^2-X^2/4)
Therefore X=36.950

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A snail crawled of a centimeter in 2 minutes. At that rate, how far could the snail crawl in 1

vekshin1

Answer:30 centimeters in 1 minute

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2 years ago

The area of a rectangle A = I x w represented by the expression 24x^6y^15 which could be the dimensions of the rectangle

denis23 [38]

Area of rectangle is given by:
Area=length×width
given that the area of our rectangle is 24x^6y^15. To get the possible dimensions, we shall factorize the area of our rectangle:
(24x^6y^15)
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3 years ago

Read 2 more answers

Find sin θ and cos θ if tan θ= 1/4 and sin 0>0.

Serga [27]

Answer:

$\displaystyle \sin(\theta)= \frac{\sqrt{17}}{17}$

$\displaystyle \cos(\theta)= \frac{4 \sqrt {17} }{ 17 }$

Step-by-step explanation:

We want to find sin(θ) and cos(θ) given that tan(θ) = 1/4 and sin(θ) > 0.

First, since tan(θ) and sin(θ) are both positive, cos(θ) must be positive as well.

Recall that tangent is the ratio of the opposite side to the adjacent side.

Therefore, the hypotenuse is:

$h=\sqrt{4^2+1^2}=\sqrt{16+1}=\sqrt{17}$

So, with respect to θ, the opposite side is 1, the adjacent is 4, and the hypotenuse is √17.

Then it follows that:

$\displaystyle \sin(\theta)=\frac{1}{\sqrt{17}} = \frac{\sqrt{17}}{17}$

And that:

$\displaystyle \cos(\theta)= \frac{4}{\sqrt{17}} = \frac{4 \sqrt {17} }{ 17 }$

5 0

2 years ago

What is the y-coordinate of the solution for the system of equations?

Alchen [17]

Answer:

$y=5$

Step-by-step explanation:

we have

$x-y=-11$ ----> isolate the variable x

$x=y-11$ -----> equation A

$y+7=-2x$ ----> equation B

substitute equation A in equation B

$y+7=-2(y-11)$

solve for y

$y+7=-2y+22$

$y+2y=22-7$

$3y=15$

$y=5$

7 0

3 years ago

number 3 says,"If u and v are the measures of complementary angles such that sin u =2/5 and tan v =(square root of 21) 21/2, lab

vodomira [7]

Answer and Explanation:

Using trig ratios, we can express the given values of sin u and tan v as shown below

$\begin{gathered} \sin u=\frac{opposite\text{ of angle u}}{\text{hypotenuse}}=\frac{2}{5} \\ \tan v=\frac{opposite\text{ of angle v}}{\text{hypotenuse}}=\sqrt[]{21} \end{gathered}$

So we can go ahead and label the sides of the triangle as shown below;

We can find the value of u as shown below;

$\begin{gathered} \sin u=\frac{2}{5} \\ u=\sin ^{-1}(\frac{2}{5}) \\ u=23.6^{\circ} \end{gathered}$

We can find v as shown below;

$\begin{gathered} u+v+90=180\text{ (sum of angles in a triangle)} \\ v+23.6+90=180 \\ v=180-113.6 \\ v=66.4^{\circ} \end{gathered}$

5 0

1 year ago