Answer:
A) JK and AB =
![[tex] \boxed{( \theta) = \f{12}{( \theta)} }](https://tex.z-dn.net/?f=%5Btex%5D%20%5Cboxed%7B%28%20%5Ctheta%29%20%3D%20%5Cf%7B12%7D%7B%28%20%5Ctheta%29%7D%20%7D)
So, =》 
=》 
[/tex]
B) AABC
![[tex] \boxed{( \theta) = {1}{( \theta)} }](https://tex.z-dn.net/?f=%5Btex%5D%20%5Cboxed%7B%28%20%5Ctheta%29%20%3D%20%7B1%7D%7B%28%20%5Ctheta%29%7D%20%7D)
So, 
C) AABM:
![[tex] e \fbox{: }](https://tex.z-dn.net/?f=%5Btex%5D%20e%20%5Cfbox%7B%3A%20%7D)
The value of k for which 
is 
ans[/tex]
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1) 84 hours
2) 2.4 meters
3) 4800 seconds
4) 100000grams
5)219.2 Fahrenheit degrees
Answer: The professor was not accurate with his hypothesis.
Null hypothesis: P1 = 12.5%, P2 = 42.5%, P3 = 45%
The alternate hypothesis: At least one proportion of the student will differ from the others.
Step-by-step explanation: To check if the professors hypothesis were inaccurate.
What percentage of student bought a hard copy of the book.
(25 ÷ 200) × 100 = 12.5%
What percentage of the student printed it from the web.
(85 ÷ 200) × 100 = 42.5%
What percentage of the students read it online.
(90 ÷ 200) × 100 = 45%
This means that the professor was not accurate with his hypothesis. Because the proportion of student in his hypothesis was not the same in the actual.
Therefore; the null hypothesis are
P1 = 12.5%, P2 = 42.5%, P3 = 45%
The alternative hypothesis will state that at least one of the proportion will be different from the others.
-6a+10=-4a-16
-6a+26=-4a
26=2a
A=13
Larger = 2smaller + 1 ----(1)
smaller = 2 larger - 17 ----(2)
put (2) in (1)
larger = 2(2larger-17) + 1
larger = 4larger-34+1
-3larger = - 33
so larger= 11
then smaller= 2(11)-17 = 5
answer two integers are 11 and 5
