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Mathematics

1 answer:

NeTakaya3 years ago

4 0

Answer:

The true statements are:

*The median weight for shelter A is greater than shelter B.

*The (IQR) interquartile range of shelter A is greater than the (IQR) interquartile range of shelter B.

Step-by-step explanation:

(for shelter A)

median: 21

lowest value: 8

highest value: 30

lower quartile: 17

upper quartile: 28

(IQR) interquartile range: 28 - 17 = 11

Range: 30 - 8 = 22

(for shelter B)

median: 18

lowest value: 10

highest value: 28

lower quartile: 16

upper quartile: 20

(IQR) interquartile range: 20 - 16 = 4

Range: 28 - 10 = 18

~phew!, this took me long xd, hope this helps you~

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Use the discriminant to describe the roots of each equation. Then select the best description.

tresset_1 [31]

Answer:

Imaginary roots

Step-by-step explanation:

The discriminant of a quadratic in standard form $ax^2+bx+c$ is given by $b^2-4ac$ .

Given $7x^2+1=5x$ , subtract 5x from both sides so that the quadratic is in standard form:

$7x^2-5x+1=0$

Now assign variables:

$a\implies 7$
$b\implies -5$
$c\implies 1$

The discriminant is therefore $(-5)^2-4(7)(1)=25-28=\textbf{-3}$ .

What does this tell us about the roots?

Recall that the discriminant is what is under the radical in the quadratic formula. The quadratic formula is used to find the solutions of a quadratic. Therefore, the solutions of this quadratic would be equal to $\frac{-b\pm \sqrt{-3}}{2a}$ for some $b$ and $a$ . Since the number under the radical is negative, there are no real roots to the quadratic (whenever the discriminant is negative, the are zero real solutions to the quadratic). Therefore, the quadratic has imaginary roots.