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3 years ago

Dyahnzskft - GMEEET C0DEGIRLSSSSSSS❤️❤️❤️❤️

Mathematics

1 answer:

Anna007 [38]3 years ago

7 0

Answer:

zoin in I am live and thecode is there in my question

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Please solve the worksheet. (factoring trinomials)

Vesnalui [34]

Answer:

1. (x+3)(x+1)

2. (m+4)(m+8)

3. (r-2)(r-1)

4. (x-5)(x-1)

5. (x-7)(x-3)

6. (x-11)(x-11)

7. (t-6)(t+2)

8. (p-8)(p-8)

9. (x-1)(x-9)

10. (x+5)(x+1)

11. (a+9)(a-1)

12. (y-8)(y+1)

13. (x-3)(x+1)

14. (y+13)(y+1)

15. (m+5)(m+4)

16. (x+10)(x+2)

17. (a-12)(a-2)

18. (y+9)(y+2)

19. xy(x+2+y) i think

20. ab(a-4+4b)

21. xy(x+6-7y)

5 0

3 years ago

Determine the measure of angle BZC.

dusya [7]

Answer:

70 degrees

Step-by-step explanation:

Angle BZA = Angle BZC = 20 degrees

Reason : These two angles are Vertically opposite angles.

Angle BZA + Angle BZC = 90

20 + Angle BZC = 90

Angle BZC = 90 - 20

Angle BZC = 70 degrees

8 0

3 years ago

the price of gasoline varies directly with the number of gasoline purchased Purchase 15 gallons of gasoline you pay $36.75

castortr0y [4]

The answer is 2.45 a gallon

8 0

3 years ago

Solve 3[-x + (2 x + 1)] = x - 1.

Marrrta [24]

Answer:

x= -2

Step-by-step explanation:

-3x+6x+3=x-1

3x-x= -1-3

2x= -4

x= -2

6 0

3 years ago

Read 2 more answers

A tennis tournament has 2n contestants. We want to pair them up for the first round of singles matches. Show that the number of

ddd [48]

There are

$\dbinom{2n}2 = \dfrac{(2n)!}{2! (2n-2)!}$

ways of pairing up any 2 members from the pool of $2n$ contestants. Note that

$(2n)! = 1\times2\times3\times4\times\cdots\times(2n-2)\times(2n-1)\times(2n) = (2n-2)! \times(2n-1) \times(2n)$

so that

$\dbinom{2n}2 = \dfrac{(2n)\times(2n-1)\times(2n-2)!}{2! (2n-2)!} = \boxed{n(2n-1)}$

4 0

2 years ago

Dyahnzskft - GMEEET C0DEGIRLSSSSSSS❤️❤️❤️❤️​

Dyahnzskft - GMEEET C0DEGIRLSSSSSSS❤️❤️❤️❤️