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Varvara68 [4.7K]
2 years ago
5

List four types of Web browsers​

Computers and Technology
2 answers:
Mazyrski [523]2 years ago
7 0

Answer:

interent just turn on chrome explore fire fox yahhoo

Explanation:

aleksandrvk [35]2 years ago
6 0

Answer:

internet explorer safari tor firefox

Explanation:

You might be interested in
Mark and his team are working on a project that is due for delivery in the next few days. The team is using project management t
meriva

Answer:

The correct option is;

B. Managing change

Explanation:

Change management is a process of applying methods and instruments that bring about the implementation of required changes in an organization or project such that the changes are carried out in a seamless and timely manner using a carefully laid out and thorough approach that reduces the impact of the change on the quality of service and that handles the disruptions in the project or organization brought about by the change

7 0
2 years ago
Build three classes that conform to the following interfaces. Use arrays in creating your classes (e.g., do not use the built-in
daser333 [38]

Explanation:

public class ArrayList {

private Object[] array = new Object[1];

/**

 * Places new element at location

 * @param c, element to be inserted

 * @param i, location it is to be placed

 */

public void insert(char c, int i) {

 if(i>this.size()){

  System.out.println("Index "+i +" outside of list size; max: " +this.size());

  System.exit(0);

 }

 int count = 0;

 try {

  Object[] other = new Object[this.array.length+1];

  switch(i){

     case 0:{

      other[0] = c;

      for(int j=1;j<this.array.length;j++)

       other[j] = this.array[j-1];

       

      this.array = other;

      break;

     }

     default: {

      for(int j=0;j<i;j++)

       other[j] = this.array[j];

      other[i] = c;

      for(int k=i+1;k<this.array.length;k++)

       other[k] = this.array[k-1];

      this.array = other;

      break;

     }

     }

 }

 catch(ArrayIndexOutOfBoundsException exception) {

     largerArray();

     if(++count == 2){

      System.out.println("Something went wrong.");

      System.exit(0);

     }  

 }

}

 

/**

 * Places new element at location

 * @param object, element to be inserted

 * @param index, location it is to be placed

 */

void insert(Object object, int index){

 if(index>this.size()){

  System.out.println("Index "+index +" outside of list size; max: " +this.size());

  System.exit(0);

 }

 int count = 0;

 try {

  Object[] other = new Object[this.array.length+1];

  switch(index){

     case 0:{

      other[0] = object;

      for(int j=1;j<this.array.length;j++)

       other[j] = this.array[j-1];

       

      this.array = other;

      break;

     }

     default: {

      for(int j=0;j<index;j++)

       other[j] = this.array[j];

      other[index] = object;

      for(int k=index+1;k<this.array.length;k++)

       other[k] = this.array[k];

      this.array = other;

      break;

     }

     }

 }

 catch(ArrayIndexOutOfBoundsException exception) {

     largerArray();

     if(++count == 2){

      System.out.println("Something went wrong.");

      System.exit(0);

     }  

 }

}

 

/**

 * Removes element at index

 * @param index, location to remove

 * @return temp, object removed

 */

Object remove(int index){

 if(index>this.size()){

  System.out.println("Index "+index +" outside of list size; max: " +this.size());

  System.exit(0);

 }

 Object temp = this.array[index];

 int count = 0;

 try {

  Object[] other = new Object[this.array.length-1];

  switch(index){

     case 0:{

      other[0] = this.array[1];

      for(int j=1;j<this.size();j++)

       other[j] = this.array[j+1];

       

      this.array = other;

      break;

     }

     default: {

      for(int j=0;j<index;j++)

       other[j] = this.array[j];

      for(int k=index;k<this.size();k++)

       other[k] = this.array[k+1];

      this.array = other;

      break;

     }

     }

 }

 catch(ArrayIndexOutOfBoundsException exception) {

     largerArray();

     if(++count == 2){

      System.out.println("Something went wrong.");

      System.exit(0);

     }  

 }

 return temp;

}

 

/**

 * Copies the array to a new array twice the size.

 */

public void largerArray(){

 Object[] other = new Object[this.array.length*2];

 System.arraycopy(this.array, 0, other, 0, this.array.length);

 this.array = other;

}

 

/**

 * @return true if there are null elements

 */

public boolean isEmpty() {

 boolean bool = true;

 for (Object element : this.array) {

  if(element!=null){

   bool = false;

   break;

  }

  else{

   bool = true;

   break;

 }

 }

 return bool;

}

 

/**

 * Determines the real length of the array

 * @return length of non-null elements

 */

public int size(){

 int count = 0;

 for(int i=0;i<this.array.length;i++){

  if(this.array[i]==null)

   continue;

  else

   count++;

 }

 return count;

}

 

/**

 * Converts array to string.

 * @return the Array as a string

 */

public String toString(){

 String string = "";

 for(int i=0;i<this.size();i++){

  if(i<this.size()-1)

   string += this.array[i]+", ";

  else

   string += this.array[i];

 }

 return string;

}

 

/**

 * Similar to get, imput the character, retrieve index.

 * @param object, what we're looking for

 * @return index

 */

int indexOf(Object object){

 int index = -1;

 for(int i=0;i<this.array.length;i++){

  if(this.array[i]==(object))

   index = i;

  else continue;

 }

 return index;

}

 

/**

 * @param object, Arraylist tyoe

 * @return true, if the elements of the arrays are equivalent.

 */

public boolean equals(ArrayList object){

 boolean bool = false;

 int thisLength = this.array.length;

 int objectLength = object.array.length;

 if(thisLength > objectLength){

  for(int i=0;i<this.array.length;i++)

   if(this.array[i] == object.array[i])

    bool = true;

   else{

    bool = false;

    break;

   }

 }

 else{

  for(int i=0;i<object.array.length;i++)

   if(this.array[i] == object.array[i])

    bool = true;

   else{

    bool = false;

    break;

   }

 }

 return bool;

}

 

/**

 * Getter to check what is at an index

 * @param index, location

 * @return the character at this position

 */

Object get(int index){

 return this.array[index];

}

}

6 0
2 years ago
Identify the most appropriate way to display the following research data.
VMariaS [17]

Answer:

1. Artwork of the child participants can be displayed as Picture.

Explanation:

The Art work is painting and filling different colors in different images and objects. Child make different pictures of homes, objects, fruits and vegetables and then colored them accordingly. This type of art work is displayed as picture. This work could not be displayed in the form of tables and lists and also could not shown as graphics.

Answer:

2. The changing image of public transportation is displayed as Graphics.

Explanation:

In Graphics, different images has been designed on different tools by graphic designers to display some problem and its solution in visuals. Different tools are there to make visuals. Changing image of bus transportation is also a transition from old transport system to new transportation system. So, it should displayed in the form of graphics.

Answer:

Illustrative comparison of data from the year 2010-2013 can be displayed in the form of word tables and lists.

Explanation:

In tables and list different data has been placed in specific order for the purpose of analysis of data. These tables are also designed to compare different values and things. So, the data from the year 2010-2013 can be displayed in the form of tables and list so that it can be compared and analyze from different aspects.

7 0
3 years ago
A vlan ________.
tensa zangetsu [6.8K]

A vlan can span multiple interconnected switches.

<h3>What is a vlan?</h3>

A virtual LAN (VLAN) is a logical overlay network that groups together a subset of devices that share a physical LAN, isolating the traffic for each group.

A LAN is a group of computers or other devices in the same place -- e.g., the same building or campus -- that share the same physical network.

Each virtual switch, or VLAN, is simply a number assigned to each switch port.

For example, the two switch ports in the red mini-switch might be assigned to VLAN #10 . The two ports in the orange mini-switch might be assigned to VLAN #20 .

VLANs can be used for different groups of users, departments, functions, etc., without needing to be in the same geographical area.

VLANs can help reduce IT cost, improve network security and performance, provide easier management, as well as ensuring network flexibility.

To learn more about vlan, refer

https://brainly.in/question/2890503

#SPJ4

6 0
1 year ago
How can earn more answer from brainly less than two minutes, please
Andrei [34K]
You have to answer other people’s questions.
6 0
3 years ago
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