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2 years ago

11

Ski tour sales at an agency went from $12,500 in January to $8,700 in February. Enter the value to make a true statement. Round

to the nearest whole percentage.

2 answers:

IRINA_888 [86]2 years ago

8 0

Answer:

the correct answer is 38.0%

Step-by-step explanation:

Trust me

postnew [5]2 years ago

3 0

38.0% is the nearest whole percent

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What is three eighths plus one half

Annette [7]

Answer:

0.875

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Find the first three terms of the sequence below. T n = n 2 + 3 n + 4

madam [21]

Answer:

9,14,19

Step-by-step explanation:

You seem to be giving the expression 2n+3n+4.

Now simplify

An = 5n+4

Fill in n

5(1) +4

5(2) +4

5(3)+4

After solving and simplifying you see 9, 14 and 19 are the first 3 terms.

6 0

2 years ago

A car traveled 300 meters in 30 seconds. A truck traveled 600 meters in 60 seconds. Which car was faster ?

rewona [7]

Multiply the car by 2: 300 meters x 2 = 600 meters

30 seconds x 2 = 60 seconds.

The car also traveled 600 meters in 60 seconds, so the speed of the vehicles are the same.

No vehicle was faster.

8 0

3 years ago

High-power experimental engines are being developed by the Stevens Motor Company for use in its new sports coupe. The engineers

Maurinko [17]

Answer:

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(536.46, 603.54)

Step-by-step explanation:

<u><em>Step:-1</em></u>

Given that the mean of the Population = 540HP

Given that the size of the sample 'n' = 9

Given that the mean of the sample = 570HP

Given that the sample standard deviation = 30HP

<u><em>Step(ii):-</em></u>

<u><em>Degrees of freedom = n-1 =9-1 =8</em></u>

<u><em>t₀.₀₀₅ = 3.3554</em></u>

The 99% of a confidence interval for the average maximum HP for the experimental engine.

$(x^{-} - t_{\frac{0.01}{2} ,8} \frac{S.D}{\sqrt{n} } ,x^{2} + t_{\frac{0.01}{2},8 } \frac{S.D}{\sqrt{n} } )$

$(570-3.354\frac{30}{\sqrt{9} } , 570+3.354\frac{30}{\sqrt{9} } )$

(570 - 33.54 , 570+33.54)

(536.46 , 603.54)

<u><em>Final answer</em></u> :-

<em>The 99% of a confidence interval for the average maximum HP for the experimental engine.</em>

<em>(536.46, 603.54)</em>

<em></em>

4 0

2 years ago

An advertising agency notices that approximately 1 in 50 potential buyers of a product sees a given magazine ad, and 1 in 8 sees

zheka24 [161]

Answer:

Probability = 0.12025

Step-by-step explanation:

P (Am) = 1/50 = 0.02 {Magazine ad}

P (At) = 1/8 = 0.125 {Television ad}

P (Am ∩ At ) = 1/100 = 0.01 {Both ads}

P (Am U At) = P (Am) + P (At) - P (Am ∩ At )

= 0.02 + 0.125 - 0.01

P (Am U At) = 0.135 {Person sees either ad}

P (Am' ∩ At') = 1 - P (Am U At)

P (Am' ∩ At') = 1 - 0.135 = 0.865 {Person sees none ad}

Prob (Purchase) = Prob (Purchase with ad) + Prob (purchase without ad)

P (P/ A) = 1/4 = 0.25 , P (P / A') = 1/10 = 0.1

P (P) = (0.25) (0.135) + (0.1) (0.865)

= 0.03375 + 0.0865

0.12025

7 0

2 years ago