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levacccp [35]
2 years ago
15

Jonathan bought 6 cans of paint and 2/3 of a pint of special paint additive formulated to reduce mildew. Before painting his hou

se, he divided the additive equally among the 6 cans of paint. How much additive did he put in each can?
Mathematics
1 answer:
gayaneshka [121]2 years ago
5 0

Answer:

1/9 pint

or 2/9 cup

Step-by-step explanation:

This question is asking us to <em>divide </em>2/3 pint among 6 cans.

2/3 ÷ 6

2/3 × 1/6

 = 2/18

 = 1/9 pint or 2/9 cup additive

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Verizon [17]

ANSWER

Frequency=2

Midline =3

Amplitude =5

Period =π

EXPLANATION

We have:

f(x) = 5 \cos(x)  + 3

The given function is of the form;

f(x) = a\cos(bx)  + c

where

a=|5| =5 is the amplitude

and b=2 is the frequency.

and 2π/b=2π/2=π

The range of the given function is

8≤y≤-2

The midline is

\frac{8  + - 2}{2}  =  \frac{6}{2}  = 3

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If tan ⁡x=12/5, and 0°
Charra [1.4K]

The value of sin(2x) is \frac{120}{169}

Explanation:

Given that tan x =\frac{12}{5}

The formula for sin(2x) is \sin (2 x)=2 \sin x \cos x

Since, \tan x=\frac{o p p}{a d j}

Also, it is given that tan x =\frac{12}{5}

Thus, opp=12 and adj=5

To find the hypotenuse, let us use the pythagoras theorem,

\begin{aligned}h y p &=\sqrt{12^{2}+5^{2}} \\&=\sqrt{144+25} \\&=\sqrt{169} \\&=13\end{aligned}

Now, we can find the value of sin x and cos x.

\sin x=\frac{\text { opp }}{h y p}=\frac{12}{13}

\cos x=\frac{a d j}{h y p}=\frac{5}{13}

Now, substituting these values in the formula for sin 2x, we get,

\begin{aligned}\sin (2 x) &=2 \sin x \cos x \\&=2\left(\frac{12}{13}\right)\left(\frac{5}{13}\right) \\&=\frac{120}{169}\end{aligned}

Thus, the value of sin(2x) is \frac{120}{169}

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