Given plane Π : f(x,y,z) = 4x+3y-z = -1
Need to find point P on Π that is closest to the origin O=(0,0,0).
Solution:
First step: check if O is on the plane Π : f(0,0,0)=0 ≠ -1 => O is not on Π
Next:
We know that the required point must lie on the normal vector <4,3,-1> passing through the origin, i.e.
P=(0,0,0)+k<4,3,-1> = (4k,3k,-k)
For P to lie on plane Π , it must satisfy
4(4k)+3(3k)-(-k)=-1
Solving for k
k=-1/26
=>
Point P is (4k,3k,-k) = (-4/26, -3/26, 1/26) = (-2/13, -3/26, 1/26)
because P is on the normal vector originating from the origin, and it satisfies the equation of plane Π
Answer: P(-2/13, -3/26, 1/26) is the point on Π closest to the origin.
Spending money on a game
Giving money to charity
Buying food at a supermarket
Lending money to a friend
Answer: The probability is 0.46%.
The chance of each given event happening is 1/6 because there are 6 different number on the dice and only 1 number is chose.
Therefore to find the combined probability, we have to multiply all the individual probabilities.
(1/6) x (1/6) x (1/6)
Or
(1/6)^3
The answer is about 0.46%,
