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Viefleur [7K]
2 years ago
7

What is the name of N2Cl4? Explain how you determined the bond type and the steps you used to determine the naming convention fo

r the compound.
Chemistry
2 answers:
kifflom [539]2 years ago
7 0

Answer:

N2Cl4 is dinitrogen tetrachloride.

Explanation:

It is a covalent bond because they are sharing electrons between two non-metals.

N2 should be dinitrogen since the N is nitrogen and the 2 is for 2 of the Ns.

Cl4 (the second part of the compound) should be named like an ion and the prefix. for the prefix: tetra (since there are 4) and chlorIDE since we are naming it like an ion. So Cl4 becomes tetrachloride.

In the end, the compound should be named dinitrogen tetrachloride.

ioda2 years ago
5 0

Answer:

dinitrogen tetrachloride. it is composed of non-metals. Therefore, N2Cl4 is a covalent compound. The first nonmetal is named accordingly and uses all numerical prefixes besides mono. The other nonmetal has its base name but has its ending that is changed to –ide. It will as well use any of the numerical prefixes.

Explanation:

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maksim [4K]
<h3>Answer:</h3>

3.0 × 10²³ molecules AgNO₃

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
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<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

85 g AgNO₃ (silver nitrate)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of Ag - 107.87 g/mol

[PT] Molar Mass of N - 14.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of AgNO₃ - 107.87 + 14.01 + 3(16.00) = 169.88 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 85 \ g \ AgNO_3(\frac{1 \ mol \ AgNO_3}{169.88 \ g \ AgNO_3})(\frac{6.022 \cdot 10^{23} \ molecules \ AgNO_3}{1 \ mol \ AgNO_3})
  2. Multiply/Divide:                                                                                                \displaystyle 3.01313 \cdot 10^{23} \ molecules \ AgNO_3

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

3.01313 × 10²³ molecules AgNO₃ ≈ 3.0 × 10²³ molecules AgNO₃

6 0
3 years ago
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Explanation:

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3. How many molecules are in 2.10 moles of H2O?
AnnZ [28]

Answer:

<h2>1.264 × 10²⁴ molecules</h2>

Explanation:

The number of molecules can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 2.10 × 6.02 × 10²³

We have the final answer as

<h3>1.264 × 10²⁴ molecules</h3>

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5 0
3 years ago
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