I think the correct answer from the choices listed above is the first option. Burning biomass releases fewer toxins than coal. When coal is burned, it releases<span> many </span>toxic<span> gases and pollutants into the atmosphere which is not favorable to the people and for the environment. Hope this answers the question.</span>
Answer:
Oxygen is more electronegative than sulphur
Explanation:
Bond angle of a molecule is related to the electronegativity of the central atom. The more electronegative the central atom is, the greater the bond angle.
As electronegativity of the central atom increases, the magnitude of bond pair- bond pair repulsion increases leading to increase in bond angle.
Hence, oxygen, being more electronegative than sulphur asserts a greater bond pair- bond pair repulsion leading to a greater bond angle in water.
Answer: The approximate pressure of the gas after it is heated to 278 K is 0.468 atm.
Explanation:
Given:
= 178 K,
= 0.3 atm
= 278 K,
= ?
According to Gay Lussac law, at constant volume the pressure of a gas is directly proportional to the temperature.
Formula used to calculate the pressure is as follows.

Substitute the values into above formula is as follows.

Thus, we can conclude that the approximate pressure of the gas after it is heated to 278 K is 0.468 atm.
The bonds in the SiCl₄ molecules will be more polar.
The polarity of bonds within a molecule depends on the difference in electronegativity of the atoms that are involved in the bond. Chlorine is a more electronegative atom than iodine. Therefore, the electrons in the Si-Cl bond will be more concentrated near the Cl, creating polarity in the bond. Iodine is not as electronegative, so it will not result in a very polarized Si-I bond
Explanation:
The given reaction is as follows.

Hence, number of moles of NaOH are as follows.
n = 
= 0.005 mol
After the addition of 25 ml of base, the pH of a solution is 3.62. Hence, moles of NaOH is 25 ml base are as follows.
n = 
= 0.0025 mol
According to ICE table,

Initial: 0.005 mol 0.0025 mol 0 0
Change: -0.0025 mol -0.0025 mol +0.0025 mol
Equibm: 0.0025 mol 0 0.0025 mol
Hence, concentrations of HA and NaA are calculated as follows.
[HA] = 
[NaA] = 
![[A^{-}] = [NaA] = \frac{0.0025 mol}{V}](https://tex.z-dn.net/?f=%5BA%5E%7B-%7D%5D%20%3D%20%5BNaA%5D%20%3D%20%5Cfrac%7B0.0025%20mol%7D%7BV%7D)
Now, we will calculate the
value as follows.
pH = 
![pK_{a} = pH - log \frac{[A^{-}]}{[HA]}](https://tex.z-dn.net/?f=pK_%7Ba%7D%20%3D%20pH%20-%20log%20%5Cfrac%7B%5BA%5E%7B-%7D%5D%7D%7B%5BHA%5D%7D)
= 
= 3.42
Thus, we can conclude that
of the weak acid is 3.42.