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Vlada [557]
3 years ago
14

A line includes the points (6,9) and (14, 17). What is its equation in slope-intercept form?

Mathematics
1 answer:
Firlakuza [10]3 years ago
5 0

Answer:

y = x + 3

Step-by-step explanation:

Given: (6,9)  (14, 17)

m=\frac{y_{2}-y_{1}  }{x_{2}-x_{1}  } = \frac{17-9}{14-6}=\frac{8}{8}=1

slope, m = 1

Equation of line ⇒ y=mx+b

y = 9 , x = 6 , m = 1, b = ?

9 = 1*6 + b

9 = 6 + b

b = 9 - 6 = 3

Therefore, the equation of line will be:

y = 1x + 3

y = x + 3

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Step-by-step explanation:

5 0
2 years ago
rock is thrown upward with a velocity of 27 meters per second from the top of a 23 meter high cliff and it misses the cliff on t
ahrayia [7]

the rock will be at 11 meters from the ground level after 5.92 seconds

Step-by-step explanation:

The motion of the rock is a free-fall motion, since the rock is acted upon the force of gravity only. Therefore, it is a uniformly accelerated motion, so its position at time t is given by the equation:

y=h+ut+\frac{1}{2}at^2

where

h = 23 m is the initial height

u = 27 m/s is the initial velocity, upward

a=g=-9.8 m/s^2 is the acceleration of gravity, downward

t is the time

We want to find the time t at which the position of the rock is

y = 11 m

Substituting and re-arranging the equation, we find

11=23+27t-4.9t^2\\4.9t^2-27t-12=0

This is a second-order equation, which has solutions:

t=\frac{27\pm \sqrt{(-27)^2-4(4.9)(-12)}}{2(4.9)}=\frac{27\pm \sqrt{964.2}}{9.8}

So

t_1 = -0.41 s

t_2=5.92 s

The first solution is negative so we neglect it: therefore, the rock will be at 11 meters from the ground level after 5.92 seconds.

Learn more about free fall:

brainly.com/question/1748290

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8 0
3 years ago
Suppose the population standard deviation is σ = 5 , an SRS of n = 100 is obtained, and the confidence level is chosen to be 98%
beks73 [17]

Answer:

1.165.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.98}{2} = 0.01

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.01 = 0.99, so z = 2.33

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

In this problem, we have that:

\sigma = 5, n = 100. So

M = z*\frac{\sigma}{\sqrt{n}}

M = 2.33*\frac{5}{\sqrt{100}} = 1.165

So the correct answer is:

1.165.

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3 years ago
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B) two real roots is the answer because it is bigger than 0.
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