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bulgar [2K]
2 years ago
9

A taxpayer's most advantageous tax benefit is A) a tax deduction. B) a depletion allowance. C) a tax credit. D) straight-line de

preciation.
Business
1 answer:
ss7ja [257]2 years ago
4 0

Answer:

D) a tax credit.

Explanation:

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Registration is a must for sole proprietorships. <br><br> a. True <br><br> b. False
kifflom [539]
A, true. hope this helped you!!!
5 0
3 years ago
The changes in account balances of the Vel Corporation during Year 6 are presented below: Increase Assets $356,000 Liabilities 1
zzz [600]

Answer:

b. $ 36,000

Explanation:

The fundamental accounting equation is

Assets = Liabilities + Stockholders Equity

Per the data provided in the question regarding changes in account balances

$ 356,000 = $108,000 + (240,000+24,000)

$ 356,000 = $ 372,000

= - ($ 14,000)

Since the data provides that a dividend payment of $ 52,000 has been made, we have to add it to our differential balance to get the income for the year.

$ - 14,000 + $ 52,000  = $ 36,000

6 0
2 years ago
what is the best strategy to avoid paying interest on your credit cards? who ever answers fast enough gets 30 points, so i'd hur
adoni [48]

Pay off your balance every month.

Explanation

Avoid paying interest on your credit card purchases by paying the full balance each billing cycle. Resist the temptation to spend more than you can pay for any given month, and you'll enjoy the benefits of using a credit card without interest charged

5 0
2 years ago
Read 2 more answers
(a) What is the average useful power output of a person who does 6.00×106 J of useful work in 8.00 h? (b) Working at this rate,
netineya [11]

Answer:

(a) 208.33 J/s

(b) 141.12 s

Explanation:

(a) Energy is the rate of doing work.

Work is the product of power and time

Work = Power × Time

Power = Work/time

where work is in joule and time is in seconds

Given that work = 6 × 10^{6}

Time = 8 h = 8 × 60 × 60

 = 28800 seconds

Average useful power = \frac{6 ×10^{6} }{28800}

                                     = 208.33 J/s

(b) Given

mass = 2000kg , using g = 9.8 m/s2

Force = 2000 × 9.8

          = 19600N

Work =  Force × Distance ( considering that Work done to lift his body can be omitted because it is not considered useful output here)

Work = 19600 × 1.5

        = 29,400J

Time taken = Work/Power

                  = \frac{29400}{208.33} \\

                  = 141.12s

                  ≈ 2 Minutes 21 Seconds

At the rate of 208.33J/s, it will take the person 141.12 seconds to lift 2000 kg of bricks 1.50 m to a platform.

5 0
3 years ago
Inventory is an extra cost associated with the Aggregate Production Planning strategy of _____
goldfiish [28.3K]

Answer:

Production

Explanation:

6 0
2 years ago
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