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MAXImum [283]
3 years ago
7

Which statement is true?

Chemistry
1 answer:
Daniel [21]3 years ago
3 0

Answer:

i guess the answer is heat refers to a quantity.

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Hello we are twins683838383833838383838888833838
pychu [463]

Answer:

sure

Explanation:

5 0
4 years ago
What category of elements does krypton gas belong to?
levacccp [35]
C. Krypton is a noble gas, on the right side of the period table, making it a non-metal.
6 0
4 years ago
Read 2 more answers
For each of the esters provided, identify the alcohol and the carboxylic acid that reacted.
Veronika [31]

Answer:

52. The alcohol USED => methanol, CH3OH

The carboxylic acid USED => propanoic acid, CH3CH2COOH.

53. The alcohol USED => Ethanol, CH2CH3OH

The carboxylic acid USED => Formic acid, HCOOH.

Explanation:

52. To obtain Methyl propanoate, CH3CH2COOCH3, we simply react propanoic, CH3CH2COOH and methanol, CH3OH together as shown below:

CH3CH2COOH + CH3OH —> CH3CH2COOCH3 + H2O

The alcohol used: methanol, CH3OH

The carboxylic acid used: propanoic acid, CH3CH2COOH.

53. To obtain Ethyl methanoate, HCOOCH2CH3, we simply react

Formic acid, HCOOH and ethanol, CH3CH2OH together as show below:

HCOOH + CH3CH2OH —> HCOOCH2CH3 + H2O

The alcohol USED => Ethanol, CH2CH3OH

The carboxylic acid USED => Formic acid, HCOOH.

7 0
3 years ago
The following anions can be separated by precipitation as silver salts: Cl- , Br- , I- , CrO4 2-. If Ag is added to a solution c
dalvyx [7]

Answer:

AgI, AgBr, AgCl and Ag₂CrO₄

Explanation:

Ksp (product solubility constant) is defined as the equilibrium constant of the general reaction:

XₐYₙ(s) → aXⁿ⁺(aq) + nYᵃ⁻(aq)

<em>Where X is cation and Y is anion.</em>

Ksp = [aXⁿ⁺]ᵃ [nYᵃ⁻]ⁿ

The presence of XₐYₙ(s) produce ax moles of aXⁿ⁺ and nx moles of Yᵃ⁻. <em>Where X is the solubility of the compound.</em>

Replacing in Ksp:

Ksp = [ax]ᵃ [nx]ⁿ

Solving for x, Solubility (S) is defined as:

S = \sqrt[n+a]{\frac{Ksp}{a^{a} n^n} }

For AgCl, Ag₂CrO₄, AgBr and AgI solubilities are:

S = \sqrt[2]{\frac{1.8x10^{-10}}{1} } = 1.34x10⁻⁵M

S = \sqrt[3]{\frac{1.1x10^{-12}}{4} } = 6.50x10⁻⁵M

S = \sqrt[2]{\frac{5.4x10^{-13}}{1} } = 7.35x10⁻⁷M

S = \sqrt[2]{\frac{8.5^{-17}}{1} } = 9.22x10⁻⁹M

The lower solubility is the first compound in precipitate, thus, order of precipitation is:

<em>AgI, AgBr, AgCl and Ag₂CrO₄</em>

8 0
3 years ago
Explain what states are changing in these examples
miv72 [106K]
(A) ice to water
(B) water to water vapor
8 0
3 years ago
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