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4 years ago

What category of elements does krypton gas belong to?

Chemistry

2 answers:

levacccp [35]4 years ago

6 0

C. Krypton is a noble gas, on the right side of the period table, making it a non-metal.

Natalka [10]4 years ago

3 0

The correct answer is C. Non-metals

Explanation:

Krypton is one of the 118 chemical elements that have been identified. Krypton's main characteristics include lack of odor, color, and low reactivity, due to this, this element is classified as a noble gas and in the periodic table is part of the Group 18. Moreover, Krypton is part of the non-metals category that includes elements with low density, melting/boiling point, and conductivity, which are all features exhibit by Krypton as this has low electricity and heat conductivity, low density, low melting point (around -157 °C) and low boiling point (-153 °C). Thus, the category Krypton gas and in general Krypton belongs to is non-metals.

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When the following equation is balanced using the smallest possible integers, what is the number in front of the substance in bo

weeeeeb [17]

The balanced equation :

8Al + 3Fe₃O₄→ 4Al₂O₃ + 9Fe

You just have to look for which element is in bold because the question is not clear

<h3>Further explanation</h3>

Equalization of chemical reaction equations can be done using variables. Steps in equalizing the reaction equation:

1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c etc.

2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index between reactant and product

3. Select the coefficient of the substance with the most complex chemical formula equal to 1

Reaction

Al + Fe₃O₄→ Al₂O₃ + Fe

give a coefficient

aAl + Fe₃O₄→ bAl₂O₃ + cFe

O, left=4, right=3b⇒3b=4⇒b=4/3

Al, left=a, right=2b⇒a=2b⇒a=2.4/3⇒a=8/3

Fe, left=3, right=c⇒c=3

The equation becomes :

8/3Al + Fe₃O₄→ 4/3Al₂O₃ + 3Fe x3

8Al + 3Fe₃O₄→ 4Al₂O₃ + 9Fe

7 0

3 years ago

The reaction rate is k[Ce4+][Mn2+] for the following reaction: 2Ce4+(aq) + Tl+(aq) + Mn2+(aq) → 2Ce3+(aq) + Tl3+(aq) + Mn2+(aq W

sdas [7]

Answer:

Manganese (II) ion, Mn²⁺

Explanation:

Hello,

In this case, given the overall reaction:

$2Ce^{4+}(aq) + Tl^+(aq) + Mn^{2+}(aq) \rightarrow 2Ce^{3+}(aq) + Tl^{3+}(aq) + Mn^{2+}(aq)$

Thus, since manganese (II) ion, Mn²⁺ is both at the reactant and products, we infer it is catalyst, since catalysts are firstly consumed but finally regenerated once the reaction has gone to completion. Moreover, since inner steps are needed to obtain it, we can infer that the given rate law corresponds to the slowest step that is related with the initial collisions between Ce⁴⁺ and Mn²⁺

Best regards.

8 0

4 years ago

Which of following affects liquifaction of gases except

iogann1982 [59]

Answer:

pressure

Explanation:

gas convert to liquid at high pressure.

4 0

3 years ago

PLS help

viktelen [127]

Answer:

d . Sc2O5

Explanation:

Hello,

In this case, when forming oxides from a metal and oxygen, for us to find out each element's subscript, we must exchange them as shown below, considering +5 for scandium:

$Sc^{+5}_2O^{-2}_5$

For that reason, the answer is d . Sc2O5

Best regards.

3 0

3 years ago

Read 2 more answers

Given a compound with a mw of 169 amu having 13.60% na, 8.29% n, 35.51% c, 4.77% h, and 37.85% o, determine the number of each a

Arisa [49]

1) Percent composition

<span>Na: 13.60%,
N:     8.29%
C:    35.51%
H: 4.77%
O:   37.85%
     -------------
       100.02%

2) Convert mass percent to molar composition

For that, divide the percent of each element by its atomic mass.

</span>
<span>Na: 13.60 / 22.99 = 0.5916
N:     8.29 / 14.01 = 0.5917
C:    35.51 / 12.01 = 2.9567
H: 4.77 / 1.01 = 4.7228
O:   37.85 / 16.00 = 2.3656

3) Divide each number by the smallest one:

</span>
<span><span>Na: 0.5916 / 0.5916 = 1.0
N:     0.5917 / 0.5916 = 1.0
C:    2.9567 / 0.5916 = 5.0
H: 4.7228 / 0.5916 = 8.0
O:   2.3656</span> / 0.5916 = 4.0

4) State the empirical formula: Na N C5 H8 O4

5) Calculate the mass of the empirical formula:

Multiplicate the number of each atoms times the atomic mass corresponding atomic mass of the atom.

1 * 22.99 + 1 * 14.01 + 5 * 12.01 + 8 * 1.01 + 4 * 16.00 = 169.13

6) Divide the molar mass by the mass of the empirical formula:

169 / 169.13 = 1

7) Conclusion: the molecular formula is Na N C5 H8 O4, so the number of atoms present in the compound formula are:

Na: 1
N: 1
C: 5
N: 8
O: 4
</span>

5 0

3 years ago

Read 2 more answers