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Phantasy [73]
3 years ago
13

Camila ubicó 90 botellas en una estantería de un supermercado y de ellas eran de jugo sin azúcar.Si los jugos sin azúcar tienen

tres sabores diferentes y Camila puso la misma cantidad de cada sabor en la estantería, ¿con cuál de las siguientes operaciones se calcula la cantidad de botellas de jugo sin azúcar de cada sabor que puso Camila en la estantería?
Mathematics
1 answer:
Tom [10]3 years ago
3 0

Camila puso 30 botellas de cada sabor en la estantería.

Dado que Camila ubicó 90 botellas en una estantería de un supermercado, y los jugos sin azúcar tienen tres sabores diferentes y Camila puso la misma cantidad de cada sabor en la estantería, para determinar la cantidad de botellas de jugo sin azúcar de cada sabor que puso Camila en la estantería se debe realizar el siguiente cálculo:

  • 90/3 = X
  • 30 = X

Por lo tanto, Camila puso 30 botellas de cada sabor en la estantería.

Aprende más en brainly.com/question/16991787

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How do you find the midpoint of a line segment
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3 0
3 years ago
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2(a-7)=a+4<br> 15 6<br>PLS HELPPPPPPPPPPP​
muminat

Answer:

a = 18

Step-by-step explanation:

2(a-7)=a+4

Distribute 2 into left side: 2a -14 = a + 4

subtract a from both sides  2a-a-14 = a+4-a

Simplify: a  - 14 = 4

Add 14 to both sides: a - 14 + 14 = 4 +14

Simplify:   a = 18

If wanted, plug a into original to double check work:

plug in: 2 (18-7) = 18+4

do parenthesis first: 2 (11) = 18+4

do multiplication : 22 = 18+4

additions: 22 =22

a = 18 is correct.

8 0
3 years ago
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What types of numbers are undefined when they are under a radical sign? If you were dealing with the number √-1, would it be def
Misha Larkins [42]
The square root of a a negative integer is imaginary.
It would still be a negative under a square root if you multiplied it by 2, therefor it will still be imaginary, or I’m assuming as your book calls it, undefined.
2•(sqrt-1) = 2sqrt-1

If you add a number to -1 itself, specifically 1 or greater it will become a positive number or 0 assuming you just add 1. In that case it would be defined.
-1 + 1 = 0
-1 + 2 = 1

If you add a number to the entire thing “sqrt-1” it will not be defined.
(sqrt-1) + 1 = 1+ (sqrt-1)

If you subtract a number it will still have a negative under a square root, meaning it would be undefined.
(sqrt-1) + 1 = 1 + (sqrt-1)

however if you subtract a negative number from -1 itself, you end up getting a positive number or zero. (Subtracting a negative number is adding because the negative signs cancel out).
-1 - -1 = 0
-1 - -2 = 1

If you squared it you would get -1, which is defined
sqrt-1 • sqrt-1 = -1

and if you cubed it, you would get a negative under a square root again, therefor it would be undefined.
sqrt-1 • sqrt-1 • sqrt-1 = -1 • sqrt-1 = -1(sqrt-1)

Sorry if this answer is confusing, I don’t have a scientific keyboard, I’ll get one soon.
8 0
3 years ago
you are adding 3 2/3+2 2/3 using fraction strips explain how you rename the fraction part of the problem
garri49 [273]
We have to add 3 2/3 + 2 2/3 using fraction strips. 3 2/3 and 2 2/3 are the mixed numbers. The mixed numbers consists of a whole number and a fraction. If we want to add those numbers we shoukld change them into improper fractions: 3 2/3 = ( 3 * 3 + 2 ) / 3 = 11 / 3; 2 2/3 = ( 2 * 3 + 2 ) / 2 = 8 / 3. Finally: 11 / 3 + 8 / 3 = ( 11 + 8 ) / 3 = 20 / 3 = 6 2/3. Answer: You reneme it turning them into improper fractions<span>. </span>
4 0
3 years ago
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