Answer:
IJ = 5.81 ft
To the nearest tenth = 10 ft
Step-by-step explanation:
ΔHIJ is a right angle triangle.
∠J=90°
∠H=71°
JH = 2
IJ = ?
∠I = 180 - (∠J+∠H)
∠l = 180-(90+71)
∠l = 180 - 161
∠l = 19°
Tan ∠l =.JH / IJ
Tan 19 = 2/IJ
0.3443 * IJ = 2
IJ = 2/0.3443
IJ = 5.81 ft
To the nearest tenth = 10 ft
*see attachment for diagram
Answer:
C.KM = 15
D.KL = 17
F.Perimeter or triangle JKL = 50
Step-by-step explanation:
Given:
JL = 16,
KM = 4x-1
JK = 6x - 7
KL = 5x - 3
✔️Thus, let's find the value of x
Since KM is a perpendicular bisector of JL, it means JM = LM = ½*16 = 8
KM in ∆KJM is equal to KM in ∆KLM.
The angles opposite the two corresponding congruent sides in both triangles are also congruent to each other. Therefore, the third corresponding side and angles would be congruent to each other.
Thus:
JK = KL
6x - 7 = 5x - 3 (substitution)
Collect like terms
6x - 5x = 7 - 3
x = 4
✔️Find JK:
JK = 6x - 7
Plug in the value of x
JK = 6(4) - 7
JK = 24 - 7
JK = 17
✔️Find KM:
KM = 4x - 1
Plug in the value of x
KM = 4(4) - 1
KM = 16 - 1
KM = 15
✔️Find KL:
KL = 5x - 3
Plug in the value of x
KL = 5(4) - 3
KL = 20 - 3
KL = 17
✔️Find the Perimeter of ∆KLM:
Perimeter of ∆KLM = KM + KL + LM
= 15 + 17 + 8
= 40
✔️Find the Perimeter of JKL:
Perimeter of ∆JKL = JK + KL + JL
= 17 + 17 + 16
= 50.
The correct values are:
C.KM = 15
D.KL = 17
F.Perimeter or triangle JKL = 50
Answer: Option C.
Step-by-step explanation:
Let as consider the below figure is attached below.
We know that angle between tangent and secant is half of difference of major and minor arcs.


Multiply both sides by 2.



Divide both sides by 11.

The value of x is 12.



Now,



Therefore, the correct option is C .
Because none of those are the right answer. you are given units in feet in the diagram. but are told 6 inches are lost in 4 hours. so you multiply length width and height keeping the feet then subtract .5 ft. the equation should look like V=(12×7×8)-.5
All the real number less than -3. It the first one hope this help