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dlinn [17]
3 years ago
15

you are adding 3 2/3+2 2/3 using fraction strips explain how you rename the fraction part of the problem

Mathematics
2 answers:
Mkey [24]3 years ago
5 0
For this case we have the following expression:
 3 \frac{2}{3} +  2\frac{2}{3}
 We can Rewrite the expression, as the sum of fractions with the same denominator.
 Rewriting the expression we have:
 \frac{9+2}{3} +  \frac{6+2}{3}
 \frac{11}{3} + \frac{8}{3}
 Then, adding both fractions we have:
 \frac{11+8}{3} =  \frac{19}{3}
 Answer:
 
The result of the given expression is:
 
\frac{19}{3}
garri49 [273]3 years ago
4 0
We have to add 3 2/3 + 2 2/3 using fraction strips. 3 2/3 and 2 2/3 are the mixed numbers. The mixed numbers consists of a whole number and a fraction. If we want to add those numbers we shoukld change them into improper fractions: 3 2/3 = ( 3 * 3 + 2 ) / 3 = 11 / 3; 2 2/3 = ( 2 * 3 + 2 ) / 2 = 8 / 3. Finally: 11 / 3 + 8 / 3 = ( 11 + 8 ) / 3 = 20 / 3 = 6 2/3. Answer: You reneme it turning them into improper fractions<span>. </span>
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The area of the regular hexagon is 169.74 ft2 what is the perimeter, rounded to the nearest tenth
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Answer:

Perimeter of given regular hexagon is <em>48.5 ft</em>.

Step-by-step explanation:

Let <em>ABCDEF</em> be the regular hexagon as shown in the attached figure.

<em>O</em> be the intersection point of the diagonals <em>EB</em>, <em>FC </em>and <em>AD</em>.

As per the property of regular hexagon, all the 6 triangles formed are equilateral triangles.

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\triangle EOD, \triangle DOC, \triangle BOC, \triangle AOB, \triangle AOF , \triangle FOE are equilateral \triangle s.

Area of an equilateral \triangle is defined as :

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