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3 years ago

Whole numbers greater than zero are

Mathematics

2 answers:

grandymaker [24]3 years ago

4 0

Answer:

Natural numbers, because they consist of 1, 2, 3, etc...

Nuetrik [128]3 years ago

3 0

Answer:

integers

Step-by-step explanation:

integers is what it is called

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A bookstore sells paperback fiction books in excellent condition for $2.50 and in fair condition for $0.50. Write an expression

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2 years ago

How many solutions will the following system of linear equations have? –2x + 4y = –7 y= -1/2x + 5 A. 0 B. 1 C. 2 D. infinite

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B. 1

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2 years ago

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Sal was tired of waiting for Amir to show up at their meeting place, so he started running at an average speed of 4.5 mph withou

sergiy2304 [10]

A=-.25+6.7t, s=.75+4.5t when Amir catches up a=s so:

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2 years ago

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What is 345.5 plus three tenths ?

vekshin1

Answer:

345.8

Step-by-step explanation:

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3 years ago

If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe

Natalka [10]

Answer:

They encircle the planet $3.76\times 10^{11}$ times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is $6.022\times 10^{23}$

Thus, the number of dust particles is:

$2.5\times 6.022\times 10^{23}=15.055\times 10^{23}$

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: $10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m$

If we line up the particles the distance they could cover is:

$15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}$

Circumference in meters:

$40,076km\times \frac{1000m}{1km}=40,076,000 m$

Therefore,

$\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}$

Hence, they encircle the planet $3.76\times 10^{11}$ times.

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3 years ago