16=2/3 times number of students
times both sides by 3
48=2 times number of students
divide both sides by 2
24=number of students
there aer 24 students i the club
We are given: The year of the empire fell = 1610.
We have x as a variable that represents the year after the given year 1610.
According to problem, the year after the year number 1610 will have a number that greater than 1610.
We can make a statement for inequality to be written.
"The year after the 1610 is greater than 1610".
The year after the 1610 is x and we use gerater than symbol >.
So, we can setup an inequality as:
x > 1610 : It can be read as x is greater than 1610.
Solution for 47 is what percent of 61:
47:61*100 =
(47*100):61 =
4700:61 = 77.05
Now we have: 47 is what percent of 61 = 77.05
Question: 47 is what percent of 61?
Percentage solution with steps:
Step 1: We make the assumption that 61 is 100% since it is our output value.
Step 2: We next represent the value we seek with $x$x.
Step 3: From step 1, it follows that $100\%=61$100%=61.
Step 4: In the same vein, $x\%=47$x%=47.
Step 5: This gives us a pair of simple equations:
$100\%=61(1)$100%=61(1).
$x\%=47(2)$x%=47(2).
Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS
(left hand side) of both equations have the same unit (%); we have
$\frac{100\%}{x\%}=\frac{61}{47}$
100%
x%=
61
47
Step 7: Taking the inverse (or reciprocal) of both sides yields
$\frac{x\%}{100\%}=\frac{47}{61}$
x%
100%=
47
61
$\Rightarrow x=77.05\%$⇒x=77.05%
Therefore, $47$47 is $77.05\%$77.05% of $61$61.
