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steposvetlana [31]
2 years ago
12

Solving inequalities 3n + 8 < 5

Mathematics
2 answers:
castortr0y [4]2 years ago
7 0
<h3><u><em>My frinds the answer is N < - 1</em></u></h3><h3><u><em>3n + 8 < 5</em></u></h3><h3><u><em>3n + 8 - 8 < 5 - 8</em></u></h3><h3><u><em>3n < 5 - 8</em></u></h3><h3><u><em>3n < - 3</em></u></h3><h3><u><em>3n </em></u><em>  <   </em><u><em>-3 </em></u><em>  </em></h3><h3><em> 3         3</em></h3><h3><em>n  <  </em><u><em>-3</em></u></h3><h3><em>        3</em></h3><h3><em>n < </em><u><em>-1 x 3</em></u></h3><h3><em>       1 x 3</em></h3><h3>N < - 1</h3><h3><u><em></em></u></h3>

Bezzdna [24]2 years ago
5 0

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.  Inequality Form:

<h2>n < -1</h2>

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Short Response
garik1379 [7]

Answer:

(a)2(89x+84)

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Step-by-step explanation:

The dimensions of the larger rectangular field are:

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The dimensions of the smaller rectangular soccer field are:

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(a)Area of the part of the field that is outside the soccer field

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From Part (a),

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Area of the Semicircular Fountain =\dfrac{\pi r^2}{2} =\dfrac{\pi (2x)^2}{2} =\dfrac{4x^2\pi}{2} =2x^2\pi

Area of the Field that does not include the soccer  field or the fountain.

=Area of the larger rectangular field - Area of the Soccer Field-Area of the Semicircular Fountain

=178x+168-2x^2\pi\\=2(89x+84-x^2\pi)

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