Answer:
1. d/a+c=d
2. (m+21)/5=n
3. (1/2+2q)*4=p or 2+8q=p
4. (p-2a)/2pi=r
5. {[(5c+1)/2]+c}/3=a
Answer: the leg x would equal 76.8, or 77 rounded. The actual number would be 76.8374908492.
After 6 years, the difference between owning the house and renting is $12,000.
<h3>What is the difference in owing and renting the house?</h3>
The first step is to determine the total cost of renting the house for six years.
Total cost of renting the house = rent per month x number of years x number of months in a year
1500 x 12 x 6 = $108,000
Difference = cost of owning - cost of renting
$120,000 - $108,000 = $12,000
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Using the Factor Theorem, the polynomials are given as follows:
1.
2.
3. P(x) = -0.1(x³ - 4x² - 3x + 18)
<h3>What is the Factor Theorem?</h3>
The Factor Theorem states that a polynomial function with roots is given by:
In which a is the leading coefficient.
Item a:
The parameters are:
Hence the equation is:
P(x) = (x - 1)²x²(x + 4)
P(x) = (x² - 2x + 1)(x + 4)x²
P(x) = (x³ + 2x² - 7x + 1)x²
Item b:
The roots are:
Hence:
P(x) = a(x - 4)²x(x + 4)
P(x) = a(x² - 16)x(x - 4)
P(x) = a(x³ - 16x)(x - 4)
It passes through the point x = 5, P(x) = 36, hence:
45a = 36.
a = 4/5
a = 0.8
Hence:
Item 3:
The roots are:
Hence:
P(x) = a(x - 3)²(x + 2)
P(x) = a(x² - 6x + 9)(x + 2)
P(x) = a(x³ - 4x² - 3x + 18)
For the y-intercept, x = 0, y = -1.8, hence:
18a = -1.8 -> a = -0.1
Thus the function is:
P(x) = -0.1(x³ - 4x² - 3x + 18)
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Answer:
The correct options are:
Option B) is never zero.
Option F) When x=0, y≠0
Step-by-step explanation:
Consider the provided function.
When we substitute x=0 in above function we get:
When we substitute x=-1 in above function we get:
When we substitute x=1 in above function we get:
The above function is exponential function which does not pass through the origin and the range of the function is a positive number.
The graph of the function is shown in figure 1.
Now consider the provided options.
Option A) is always greater than or equal to 1.
The option is incorrect as the value of the function is less than 1 for negative value of x.
Option B) is never zero
The option is correct.
Option C) When y=0, x=0
The option is incorrect.
Option D) When x=0, y=4
When x=0 the value of y is 1.
Thus, the option is incorrect.
Option E) is zero when x=0
When x=0 the value of is 1.
Thus, the option is incorrect.
Option F) When x=0, y≠0
The option is correct as 0≠1.