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Anestetic [448]
3 years ago
13

The table shows the distances traveled by a paper airplane.

Mathematics
2 answers:
Sergeu [11.5K]3 years ago
5 0

Answer:

   The range is 21.75 feet.

   The interquartile range is 11 feet.

b. Interpret the range and interquartile range of the data.

   The distances traveled by the paper airplane varied by no more than 21 3/4 feet.

   The middle half of the distances traveled by the paper airplane varied by no more than 11 feet.

Step-by-step explanation:

BabaBlast [244]3 years ago
4 0

Answer:

 

Step-by-step explanation:

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Please help! 3 Questions please show how you solved the problem
Masteriza [31]

Answer:

1)  (-y^2-4y-8+4y^2+6y-3)

2)  32x^5y^4z^2

3)  x^3-9x^2+14x+24

Step-by-step explanation:

Given the expression we have to simplify the expression

1)   (-y^2-4y-8)-(-4y^2-6y+3)

⇒ (-y^2-4y-8+4y^2+6y-3)

Combining like terms, we get

⇒ 3y^2+2y-11

2.)    (2x^2y^3z^2)(4xy.4x^2)

⇒ (2x^2y^3z^2)(16x^3y)

⇒ 32x^5y^4z^2

3.)   (x-4)(x^2-5x-6)

⇒ x^3-5x^2-6x-4x^2+20x+24

⇒ x^3-9x^2+14x+24

5 0
3 years ago
Simplify negative 5 minus the square root of negative 44 negative 5 minus 4 times the square root of 11 i negative 5 minus 4 i t
Anika [276]

Answer:

-5-\sqrt{-44}=-5-2\sqrt{11}i

Step-by-step explanation:

We want to simplify:

-5-\sqrt{-44}

We rewrite the expression under the radical sign to obtain:

-5-\sqrt{4\times11\times -1}

We split the expression under the radical sign to get:

-5-\sqrt{4} \times \sqrt{11} \times \sqrt{-1}

Recall that:

\sqrt{-1}=i

This implies that:

-5-\sqrt{4} \times \sqrt{11} \times \sqrt{-1}=-5-2\sqrt{11}i

Therefore -5-\sqrt{-44}=-5-2\sqrt{11}i

6 0
3 years ago
Solve, using linear combination. <br> 3x + y = 4<br> 2x + y = 4
nataly862011 [7]
X would be 0 while Y would be 4

  3x+y=4
  -(2x+y=4)
----------------
x=0

Plug in x to any of those two equations in their original form

3(0)+y=4

0 + y = 4

y = 4
8 0
3 years ago
In the "magic square" at the right, the four numbers
romanna [79]

Answer:

15

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
PLEASE HELP!!!! WORTH 20 points it’s all I have show all of your work!!!!!!!
stiv31 [10]

Answer:

Part A: [0,2], Part B: [2, 4], Part C: [8,10], Part D: 0 ft

Step-by-step explanation:

Part A:  The time between 0 seconds to 2 seconds is the time when it's increasing. There is no other time like that.

Part B: The graph shows a straight line so therefore it is staying the same.

Part C: The graph shows a sharp decline.

Part D: Starting from the 10th second, the balloon already hit to ground so it would only make sense for it to stay there...

8 0
3 years ago
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