Chebyshev’s Theorem establishes that at least 1 - 1/k² of the population lie among k standard deviations from the mean.
This means that for k = 2, 1 - 1/4 = 0.75. In other words, 75% of the total population would be the percentage of healthy adults with body temperatures that are within 2standard deviations of the mean.
The maximum value of that range would be simply μ + 2s, where μ is the mean and s the standard deviation. In the same way, the minimum value would be μ - 2s:
maximum = μ + 2s = 98.16˚F + 2*0.56˚F = 99.28˚F
minimum = μ - 2s = 98.16˚F - 2*0.56˚F = 97.04˚F
In summary, at least 75% of the amount of healthy adults have a body temperature within 2 standard deviations of 98.16˚F, that is to say, a body temperature between 97.04˚F and 99.28˚F.
1) Final expression: 
2) Final expression: 
Step-by-step explanation:
1)
The first expression is
First, we remove the 2nd bracket by changing the sign of all the terms inside:
Now we group the terms with same degree together:
Now we solve the expression in each brackets:
So, this is the final expression.
2)
The second expression is
We apply the distributive property, so we rewrite the expression as follows:
Solving both brackets,
Now we group terms of same degree together:
And solving each bracket,
So, this is the final expression.
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Hello :
13π/4 = (16-3)π/4
= 16π/4 -3π/4
13π/4 = -3π/4 +4π
tan( 13π/4) = tan ( -3π/4)= - tan ( 3π/4) =- tan( π - π/4) = - tan(- π/4)
tan( 13π/4) = -(-tan(π/4)) =tan(π/4)=1
The formula for the number of bacteria at time t is 1000 x (2^t).
The number of bacteria after one hour is 2828
The number of minutes for there to be 50,000 bacteria is 324 minutes.
<h3>What is the number of bacteria after 1 hour?
</h3>
The exponential function that can be used to determine the number of bacteria with the passage of time is:
initial population x (rate of increase)^t
1000 x (2^t).
Population after 1 hour : 1000 x 2^(60/40) = 2828
Time when there would be 50,000 bacteria : In(FV / PV) / r
Where:
- FV = future bacteria population = 50,000
- PV = present bacteria population = 1000
- r = rate of increase = 100%
In (50,000 / 1000)
In 50 / 1 = 3.91 hours x 60 = 324 minutes
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Answer:
^7 squroot5^3
Step-by-step explanation:
5x2= 10
7÷ 3= 2.5
