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GarryVolchara [31]

2 years ago

12

Kevin wants to earn more than $42 trimming trees. He charges $8 per hour and pays $6 in equipment fees. What are the possible nu

mbers of hours Kevin could trim trees?

1 answer:

aliina [53]2 years ago

4 0

Answer:

6 hours is your answer, good luck

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Please help me with this question

netineya [11]

Answer

777

Step-by-step explanation:

jnimimimimimim000

3 0

2 years ago

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Huddson has practiced a 360-back flip for months. This week, he did it perfectly 24 out of 54 times. At this rate, how many time

iris [78.8K]

Let x = perfect flips out of nine
$\frac{24}{54} = \frac{x}{9}$
$54x = 216$
$x = 4$
4 flips

5 0

2 years ago

If the point (b,15) lies on the straight line with equation Y=5x fonde the value of b ?

Andrej [43]

Answer:

b = 3

Step-by-step explanation:

Substitute the y- coordinate 15 into the equation , that is

15 = 5x ( divide both sides by 5 )

3 = x

This is the x- coordinate of the point , so b = 3

7 0

2 years ago

Jose and Kaitlyn have a contest to see who can throw a baseball the farthest. Kaitlyn wins, with a throw of 200 ft. If Jose thre

Anton [14]

All you have to do to find the answer is divide 200 by 4 to get 50. so now you know 1/4 of 200 is 50. but jose threw the ball 3/4 as far kaitlyn so you would have to multiply 50 by 3 to get 150 which is 3/4 of 200 . so 150 ft is the answer and how far jose threw the ball.

4 0

3 years ago

Read 2 more answers

he probability that the San Jose Sharks will win any given game is 0.3694 based on a 13-year win history of 382 wins out of 1034

garri49 [273]

Answer:

0.0071 = 0.71% probability that the San Jose Sharks win 9 games in the upcoming month.

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the Sharks win, or they do not. The probability of the Sharks winning a game is independent of any other game. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability that the San Jose Sharks will win any given game is 0.3694.

This means that $p = 0.3694$

An upcoming monthly schedule contains 12 games.

This means that $n = 12$

What is the probability that the San Jose Sharks win 9 games in the upcoming month?

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{12,9}.(0.3694)^{9}.(0.6306)^{3} = 0.0071$

0.0071 = 0.71% probability that the San Jose Sharks win 9 games in the upcoming month.

6 0

3 years ago