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2 years ago

14

Diego is building a fence for a rectangular garden. It needs to be at least 10 feet wide and at least 8 feet long. The fencing h

e uses costs $3 per foot. His budget is $120.

1 answer:

fredd [130]2 years ago

5 0

Answer:

240

Step-by-step explanation:

8*10=80ft *3= 240 but thats over budget

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Can someone help me im stuck

Tcecarenko [31]

Answer:

<em>(3). 500; (4) 60</em>

Step-by-step explanation:

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2 years ago

The earth has a diameter of 7917.5 mi. What is the arc length of half the earth?

Serhud [2]

Answer:

Arc length is 12436.8m

Step-by-step explanation:

arc length = $\frac{M degree}{360degree}$ * πD

where M is the angle measure of the arc

and D is the diameter

considering the earth as a circle and half the earth as a semi circle the angle measure of the arc will be = 180 degrees

$\frac{180}{360}$ * π * 7917.5 = 12436.8m

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3 years ago

In an experiment, college students were given either four quarters or a $1 bill and they could either keep the money or spend it

gavmur [86]

Answer:

a) $P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341$

b) $P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659$

c) A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

Step-by-step explanation:

Assuming the following table:

Purchased Gum Kept the Money Total

Students Given 4 Quarters 25 14 39

Students Given $1 Bill 15 29 44

Total 40 43 83

a. find the probability of randomly selecting a student who spent the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student spent the money"

For this case we want this conditional probability:

$P(A|B) =\frac{P(A and B)}{P(B)}$

We have that $P(A)= \frac{40}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{15}{83}$

And if we replace we got:

$P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341$

b. find the probability of randomly selecting a student who kept the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student kept the money"

For this case we want this conditional probability:

$P(A|B) =\frac{P(A and B)}{P(B)}$

We have that $P(A)= \frac{43}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{29}{83}$

And if we replace we got:

$P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659$

c. what do the preceding results suggest?

For this case the best solution is:

A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

3 0

3 years ago

A human resources representative claims that the proportion of employees earning more than $50,000 is less than 40%. To test thi

bearhunter [10]

Answer:

The statistic for this case would be:

$z=\frac{\hat p -p_o}{\sqrt{\frac{\hat p(1-\hat p)}{n}}}$

And replacing we got:

$z= \frac{0.436-0.4}{\sqrt{\frac{0.436*(1-0.436)}{700}}}= 1.92$

Step-by-step explanation:

For this case we have the following info:

$n =700$ represent the sample size

$X= 305$ represent the number of employees that earn more than 50000

$\hat p=\frac{305}{700}= 0.436$

We want to test the following hypothesis:

Nul hyp. $p \leq 0.4$

Alternative hyp : $p>0.4$

The statistic for this case would be:

$z=\frac{\hat p -p_o}{\sqrt{\frac{\hat p(1-\hat p)}{n}}}$

And replacing we got:

$z= \frac{0.436-0.4}{\sqrt{\frac{0.436*(1-0.436)}{700}}}= 1.92$

And the p value would be given by:

$p_v = P(z>1.922)= 0.0274$

4 0

3 years ago

What expression is equivalent to 14/15

jonny [76]

Answer:

2/3 divided by 5/7

Step-by-step explanation:

2/3 divided by 5/7 equals 14/15

7 0

2 years ago