Let's solve your equation step-by-step.
Question 1: −2(6−2x) =4(−3+x)
Step 1: Simplify both sides of the equation.
−2(6−2x) =4(−3+x)
(−2) (6) +(−2) (−2x) =(4)(−3)+(4)(x)(Distribute)
−12+4x=−12+4x
4x−12=4x−12
Step 2: Subtract 4x from both sides.
4x−12−4x=4x−12−4x
−12=−12
Step 3: Add 12 to both sides.
−12+12=−12+12
0=0
Answer: All real numbers are solutions.
Question 2:
Let's
solve your equation step-by-step.
5−1(2x+3)
=−2(4+x)
Step 1:
Simplify both sides of the equation.
5−1(2x+3)
=−2(4+x)
5+(−1)
(2x) +(−1) (3) =(−2) (4)+(−2)(x)(Distribute)
5+−2x+−3=−8+−2x
(−2x)
+(5+−3) =−2x−8(Combine Like Terms)
−2x+2=−2x−8
−2x+2=−2x−8
Step 2:
Add 2x to both sides.
−2x+2+2x=−2x−8+2x
2=−8
Step 3:
Subtract 2 from both sides.
2−2=−8−2
0=−10
Answer: There are no solutions.
Answer:
200
Step-by-step explanation:
200×4%=8
8×3=24
The original amount is $200
Answer:
No. of boxes = 10
Oranges per box = 56
Total no. of oranges = 56*10=560
No. of bad oranges = 560/40= 14
(i) Probability of bad orange = 14/560 = 1/40
(ii) no of oranges expected to be bad = 14 ( found above)
Hope it helps.............. :)
Answer:
512 student tickets.
Step-by-step explanation:
Let x be number of student tickets and y be number of adult tickets.
We have been given that at Friday's football game 1,294 tickets were sold. We can represent this information as:
We are also told that each student ticket costs $5.00, and each adult ticket costs $8.00 and 1,294 tickets were sold for a total amount of $8,816. We can represent this information as:
From equation (1) we will get,
Substituting this value in equation (2) we will get,
Therefore, 512 student tickets were purchased at Fridays football game.
Y’all need to find out on the graft but it was 0.5 will be on the last line
