Answer:
No, the two events "being in high school" and "GPA above 3.0" are not independent.
Step-by-step explanation:
If two events A,B are independent ![P(A|B)=P(A)](https://tex.z-dn.net/?f=P%28A%7CB%29%3DP%28A%29)
P(high school | above 3.0) = ![\frac{14}{40}=0.35](https://tex.z-dn.net/?f=%5Cfrac%7B14%7D%7B40%7D%3D0.35)
P(high school) =
So,0.35 ≠ 0.6
Since P(high school | above 3.0) ≠ P(high school), the events "being in high school" and "GPA above 3.0" are not independent.
The grocer prepared total 110 samples.
<em><u>Explanation</u></em>
Suppose, the total number of samples the grocer prepared is ![x](https://tex.z-dn.net/?f=x)
By lunchtime, the grocer has given out 5 fewer than half the total number of samples. So, the number of samples given out by lunchtime ![= \frac{1}{2}x -5](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B1%7D%7B2%7Dx%20-5)
Now, it is given that she gives out 50 samples before lunch. That means...
![\frac{1}{2}x -5 =50\\ \\ \frac{1}{2}x=5+50\\ \\ \frac{1}{2}x=55\\ \\ x=55*2=110](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dx%20-5%20%3D50%5C%5C%20%5C%5C%20%5Cfrac%7B1%7D%7B2%7Dx%3D5%2B50%5C%5C%20%5C%5C%20%5Cfrac%7B1%7D%7B2%7Dx%3D55%5C%5C%20%5C%5C%20x%3D55%2A2%3D110)
So, the total number of samples the grocer prepared is 110.
Answer:
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
−5−5(6x−8)=−5x+19
−5+(−5)(6x)+(−5)(−8)=−5x+19(Distribute)
−5+−30x+40=−5x+19
(−30x)+(−5+40)=−5x+19(Combine Like Terms)
−30x+35=−5x+19
−30x+35=−5x+19
Step 2: Add 5x to both sides.
−30x+35+5x=−5x+19+5x
−25x+35=19
Step 3: Subtract 35 from both sides.
−25x+35−35=19−35
−25x=−16
Step 4: Divide both sides by -25.
−25x
−25
=
−16
−25
x=
16
25
Answer:
69.12
Step-by-step explanation:
i used a calculator and the formula
Half of the cards are red and half of them are black
so the answer is 1/2
or you can say that 26 are red and 26 are black
26/52 = 1/2