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AveGali [126]
3 years ago
9

HELLO PLEASE GIVE ME THE RIGHT ANSWER ASAP THANK YOU !

Mathematics
1 answer:
seropon [69]3 years ago
5 0

\large\underline{\sf{Solution-}}

\textsf{Given expression;}\\

\rm{23 =  \frac{7}{9}(6x - 36) + 9 } \\

\rm{\longmapsto} \: 23 =  \frac{(42x - 256)}{9}  + 9 \\

\rm{\longmapsto} \: 23 =  \frac{(42x - 256 + 81)}{9}  \\

\rm{\longmapsto} \: 23 =  \frac{(42x - 175)}{9}  \\

\rm{\longmapsto} \:  \frac{23}{1}  =  \frac{(42x - 175)}{9}  \\

\textsf{By doing cross multiplication, we get}\\

\rm{\longmapsto}23(9) = 1(42x - 175) \\

\rm{\longmapsto}207 =42x - 175\\

\rm{\longmapsto} \: 42x =  - 175 - 207 \\

\rm{\longmapsto} \: 42x =  - 379 \\

\rm \therefore \: x =  -  \frac{375}{42}  \\

\textsf{Hence, the value of x will be -375/42 respectively.}\\

\textbf{Read more:}

\textsf{Similar Questions}

Solve the expression and find the value of x. [tex] \frac{x⁠…

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Irina-Kira [14]

Given:

15. \log_{\frac{1}{2}}\left(\dfrac{1}{2}\right)

17. \log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)

19. 2^{\log_2100}

To find:

The values of the given logarithms by using the properties of logarithms.

Solution:

15. We have,

\log_{\frac{1}{2}}\left(\dfrac{1}{2}\right)

Using property of logarithms, we get

\log_{\frac{1}{2}}\left(\dfrac{1}{2}\right)=1         [\because \log_aa=1]

Therefore, the value of \log_{\frac{1}{2}}\left(\dfrac{1}{2}\right) is 1.

17. We have,

\log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)

Using properties of logarithms, we get

\log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)=-\log_{\frac{3}{4}}\left(\dfrac{3}{4}\right)                    [\because \log_a\dfrac{m}{n}=-\log_a\dfrac{n}{m}]

\log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)=-1                 [\because \log_aa=1]

Therefore, the value of \log_{\frac{3}{4}}\left(\dfrac{4}{3}\right) is -1.

19. We have,

2^{\log_2100}

Using property of logarithms, we get

2^{\log_2100}=100          [\because a^{\log_ax}=x]

Therefore, the value of 2^{\log_2100} is 100.

6 0
3 years ago
Kyle drew three line segments with lengths: 2/4 inch 2/3inch, and 2/6 inch list the fractions in order from least to greatest
Sati [7]
----------------------------------------------------------------
Method 1
 ----------------------------------------------------------------
Since the numerators are the same, the smaller the denominators, the greater the fraction is.

Arranging from the least to the greatest
\dfrac{2}{6} \ , \ \dfrac{2}{4} \ , \ \dfrac{2}{3}


----------------------------------------------------------------
Method 2
----------------------------------------------------------------
Lets change all to the same denominators 

\dfrac{2}{4}  =  \dfrac{2 \times 3}{4 \times 3}  =  \dfrac{6}{12}

\dfrac{2}{3}  =  \dfrac{2 \times 4}{3 \times 4}  =  \dfrac{8}{12}

\dfrac{2}{6}  =  \dfrac{2 \times 2}{6 \times 2}  =  \dfrac{4}{12}

Now that all the denominators are the same, we can arrange the fractions by comparing the numerators. The bigger the numerators, the greater the fraction.

Arranging from the least to the greatest
\dfrac{2}{6} \  , \   \dfrac{2}{4}  \ , \   \dfrac{2}{3}
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