Answer:
511
Step-by-step explanation:
a-b = 7 ____eq 1
ab = 8 ____eq 2
a = 7 + b ___eq 3
a = 8/b ___eq 4
using simultaneous equations :
7 + b = 8/b
7b + b^2=8
b^2 + 7b - 8 =0
factorize it
b^2 + 8b - b - 8 = 0
b(b+8) -1(b+8)=0
b = 1 , -8
then a = 8/1 = 8
a =8/-8 = -1
a = 8, -1
so,
a^3 - b^3
= (8)^3-(1)^3
= 511
Answer:
Step-by-step explanation:
The answer to this problem is 4.
Answer:
y= -3x+1
Step-by-step explanation:
Let's start with the y-intercept (initial value). The y-intercept is where the line intersects the y-axis, so the x value should be 0. Here, the y-intercept is (0,1).
The slope is equivalent to the rise over run. We rise three and go to the left 1 which gives us a slope of negative 3 since we went to the left instead of the right.
Equation for a line:
y=mx+b where m is the slope and b is the y-intercept.
We plug in the slope and y-intercept in and get...
y= -3x+1
The value of the derivative at the maximum or minimum for a continuous function must be zero.
<h3>What happens with the derivative at the maximum of minimum?</h3>
So, remember that the derivative at a given value gives the slope of a tangent line to the curve at that point.
Now, also remember that maximums or minimums are points where the behavior of the curve changes (it stops going up and starts going down or things like that).
If you draw the tangent line to these points, you will see that you end with horizontal lines. And the slope of a horizontal line is zero.
So we conclude that the value of the derivative at the maximum or minimum for a continuous function must be zero.
If you want to learn more about maximums and minimums, you can read:
brainly.com/question/24701109
