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sukhopar [10]
2 years ago
5

Find the value of x in the equation below. 2.7+x=11.7

Mathematics
2 answers:
forsale [732]2 years ago
4 0

Answer:

the answer is 9

Step-by-step explanation:

djyliett [7]2 years ago
4 0
X=9 because 11.7-2.7= 9.
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Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real
hoa [83]

Answer: 0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8


Step-by-step explanation:

We know that the standard quadratic equation is  ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

b^2-4ac=(-7)^2-4(2)(-9)=49+72>0

So it has 2 real number solutions.

2. a=1, b=-4, c=4

b^2-4ac=(-4)^2-4(1)(4)=16-16=0

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0

So it has 2 real number solutions.

5. a=3, b=5, c=3

b^2-4ac=(5)^2-4(3)(3)=25-36=-9

Thus it does not has real solutions.



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3 years ago
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Zepler [3.9K]
U is right u gunna fail LOL
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3 years ago
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lukranit [14]

Answer:

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2 years ago
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Help me with the question of o.math​
Lelu [443]

Answer:

Hello,

Answer 163

Step-by-step explanation:

1,7,16,28,43,..., 10th term=?

u_1=1,u_2=7,u_2-u_1=7-1=6=2*3\\u_3=16, u_3-u_2=16-7=9=3*3\\u_4=28, u_4-u_3=28-16=12=4*3\\u_5=43, u_5-u_4=43-28=15=5*3\\\\\boxed{ u_1=1, \ u_{n+1}-u_{n}=(n+1)*3}\\\\u_{10}=163\\

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7 0
3 years ago
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Divide: (x2 – 3x – 33) = (x + 4)
katovenus [111]

Answer:

x-7-5/x+4

So answer C

Step-by-step explanation:

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