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2 years ago

steve has 18 more dollors than joe. what the algebraic expression that represents the amount of dollors steve has

Mathematics

2 answers:

Yanka [14]2 years ago

4 0

Answer: s = j + 18

Step-by-step explanation:

Let's say Steve's money can be represented as s, and Joe's money as j. Because Steve has 18 more dollars than Joe, simply add 18 to Joe's money to solve for s.

Hope it helps :) and let me know if you want me to elaborate.

dolphi86 [110]2 years ago

4 0

Answer:

s=j Steve has 18 Dollars

Step-by-step explanation:

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Cerrena [4.2K]

Answer:

C) 41 square units

Step-by-step explanation:

I am unable to provide my work at the moment. I hope the answer is enough for you. D:

6 0

3 years ago

Find three consecutive odd integers such that the sum of the smaller two is three times larger increased by seven

sukhopar [10]

Answer:

three consecutive odd integers: 2n-1 2n+1 2n+3

that the sum of the smaller two is three

times larger increased by seven: 2n-1 + 2n+1 = 3(2n+3) +7

4n = 6n+ 9 +7

4n = 6n+ 16

4n -6n = 16

-2n = 16

n = 16/(-2)

n=-8

a) 2n -1 = 2(-8) -1 = -17

b) 2n+1 = 2(-8)+1 = -15

c) 2n+1 = 2(-8)+3 = -13

Ans. -17 ; -15 ; -13

4 0

3 years ago

If three prime numbers are randomly selected from the prime numbers less than 30 and no prime number can be chosen more than onc

Dmitry [639]

Answer:

C)30%

Step-by-step explanation:

Prime numbers less than 30 are given below

2,3,5,7,11,13,17,19,23,29

We have to find the probability that sum of three prime numbers selected will be even.

We know that

Sum of any three prime number except 2 will be odd.

Total prime numbers except 2=9

Total prime numbers=10

Probability:P(E)= $\frac{favorable\;cases}{total\;number\;of\;cases}$

Probability of getting sum of three prime numbers selected will be odd= $\frac{9C_3}{10C_3}$

$nC_r=\frac{n!}{r!(n-r)!}$

By using formula

Probability of getting sum of three prime numbers selected will be odd=P(E)= $\frac{\frac{9!}{3!6!}}{\frac{10!}{3!7!}}=\frac{9!}{3!6!}\times \frac{3!\times 7\times 6!}{10\times 9!}$