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Svetradugi [14.3K]
4 years ago
11

Mary has $15 and she wants to buy some earrings. She picks one pair that costs $7.99 and two pairs that cost $2.59 each. Which s

tatement best describes if an exact total or an approximate total should be calculated?
A.
Mary can round the prices of the earrings to the nearest dollar and then add to estimate if she has enough money.

B.
Mary must add the exact cost of the three pair of earrings so she will know if she has enough money to buy the third pair.
Mathematics
2 answers:
denis23 [38]4 years ago
7 0

Answer:

B

Step-by-step explanation:

Alika [10]4 years ago
3 0
B. Estimation is good sometimes, but not in these cases.
Trust me, it's happened to me b4.
You might be interested in
Jonny has 6 apples if you take away 3 how much do you have left?
Savatey [412]

Answer:

He has 3 apples

Step-by-step explanation:

6 - 3 = 3

3 times 2 is 6

3 + 3 = 6

4 0
3 years ago
In a study to compare two different corrosion inhibitors, specimens of stainless steel were immersed for four hours in a solutio
djverab [1.8K]

Answer:

(242-220) -1.988 \sqrt{\frac{20^2}{47} +\frac{31^2}{42}}= 10.862

(242-220) +1.988 \sqrt{\frac{20^2}{47} +\frac{31^2}{42}}= 33.138

And the 95% confidence interval for the difference in the means is given by: 10.862 \leq \mu_A -\mu_B \leq 33.138

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X_A = 242 sample mean for inhibitor A

s_A = 20 sample standard deviation for inhibitor A

n_A = 47 sample size for A

\bar X_B = 220 sample mean for inhibitor B

s_B = 31 sample standard deviation for inhibitor B

n_B = 42 sample size for A

Solution to the problem

For this case the confidence interval for the difference of means is given by:

(\bar X_A -\bar X_B) \pm t_{\alpha/2} \sqrt{\frac{s^2_A}{n_A} +\frac{s^2_B}{n_B}}

The degrees of freedom are given by:

df = n_A +n_B -2 = 47+42-2= 87

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,87)".And we see that t_{\alpha/2}=1.988

And replacing we got:

(242-220) -1.988 \sqrt{\frac{20^2}{47} +\frac{31^2}{42}}= 10.862

(242-220) +1.988 \sqrt{\frac{20^2}{47} +\frac{31^2}{42}}= 33.138

And the 95% confidence interval for the difference in the means is given by: 10.862 \leq \mu_A -\mu_B \leq 33.138

4 0
3 years ago
45(1.08)30 what is the answer
Anika [276]
<span>45 x (1.08) x </span>30 = 1458

-----------------------------------------------
7 0
4 years ago
Read 2 more answers
Need an answer, please need an answer, please​
dusya [7]

Answer:

Step-by-step explanation:

1) 6  and -5

x₁ + x₂  = 6 +(-5) = 1

x₁* x₂   = 6*(-5) = -30

x² -(x₁ + x₂)x + (x₁* x₂)=0

x² - x  - 30 = 0

2) 4 and 7

x₁ + x₂  =4 + 7 = 11

x₁* x₂   = 4*7 = 28

x² - 11x + 28 = 0

3) 1 and -10

x₁ + x₂  = 1 +(-10) = -9

x₁* x₂   = 1*(-10) = -10

x²  - 9x - 10 = 0

4) -9 and 0

x₁ + x₂  = -9 + 0 = -9

x₁* x₂   = 0

x² - (-9)x  = 0

x² + 9x = 0

5)2 and 6

x₁ + x₂  = 2 + 6 = 8

x₁* x₂   = 2*6 = 12

x² -8x + 12 = 0

8) 2 +√3  and 2 - √3

x₁ + x₂  = 2+ √3 + 2 - √3 = 4

x₁* x₂   = (2 + √3)(2 - √3) = 2² - (√3)² 4 - 3 = 1

x² - 4x + 1 = 0

7 0
3 years ago
Pls HELP, WILL GAVE A 5 STAR RATING AND BRAINLIEST
bonufazy [111]

Answer:

Step-by-step explanation:

-7x-3=2-7x-5

cancel equal terms

-3=2-5

calculate the difference

-3= -3

This statement is true.

6 0
3 years ago
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