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Svetradugi [14.3K]
3 years ago
11

Mary has $15 and she wants to buy some earrings. She picks one pair that costs $7.99 and two pairs that cost $2.59 each. Which s

tatement best describes if an exact total or an approximate total should be calculated?
A.
Mary can round the prices of the earrings to the nearest dollar and then add to estimate if she has enough money.

B.
Mary must add the exact cost of the three pair of earrings so she will know if she has enough money to buy the third pair.
Mathematics
2 answers:
denis23 [38]3 years ago
7 0

Answer:

B

Step-by-step explanation:

Alika [10]3 years ago
3 0
B. Estimation is good sometimes, but not in these cases.
Trust me, it's happened to me b4.
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I’m unsure how to solve this... help?
dem82 [27]
Time taken is equal to distance divided by speed
So time is 50/5 = 10 seconds
5 0
4 years ago
Read 2 more answers
A ship travels 62.5 km in 1st hour of sailing. Starting from 2nd hour, the distance travelled per hour is x% of that in the prec
Bas_tet [7]
Speed of the ship in the second hour =  (62.5 * x ) / 100  kph.

In third hour it is  [(62 * x) / 100 ] * x/100]

is 4th hour its is the above * x/100 again  so we can now form the equation

62.5x      x          x
------- *   ----  *  ----    =  32
100      100      100

62,5 x^3 = 32,000,000
x^3 =  512,000
x = 80 <-----  Answer  to (a)

(b)  Ship travels 62.5 in first hour then  this falls by a common ratio of 0.8 each hour so we have a geometric sequence 

Dist travelled in 6 hours  =  a1  1 - r^n
                                                --------  = 62.5* (1 - 0.8^6) / 1 -0.8 = 230.56

                                               1 - r

Answer is    230.56 km 




5 0
3 years ago
A bag of marbles contains 3 blue, 4 green, and 3 red marbles. If you take out 2 marbles, what is the probability that they are b
tangare [24]
4/10. *. 3/9. = 12/90 = 2/15
3 0
3 years ago
I AM GIVING 45 POINTS TO WHOEVER GETS THIS RIGHT... plz answer corectly and try... i was working on this for sooo long. Plz try
Alexxx [7]
When you have 3 choices for each of 6 spins, the number of possible "words" is
  3^6 = 729

The number of permutations of 6 things that are 3 groups of 2 is
  6!/(2!×2!×2!) = 720/8 = 90

A) The probability of a word containing two of each of the letters is 90/729 = 10/81


The number of permutations of 6 things from two groups of different sizes is
  (2 and 4) : 6!/(2!×4!) = 15
  (3 and 3) : 6!/(3!×3!) = 20
  (4 and 2) : 15
  (5 and 1) : 6
  (6 and 0) : 1

B) The number of ways there can be at least 2 "a"s and no "b"s is
  15 + 20 + 15 + 6 + 1 = 57
The probability of a word containing at least 2 "a"s and no "b"s is 57/729 = 19/243.


_____
These numbers were verified by listing all possibilities and actually counting the ones that met your requirements.
6 0
3 years ago
Can someone help me solve these two problems? i need to find what x is.
Bond [772]

Answer:

1. x=2

2. x= 0.33

Step-by-step explanation:

1.So to start off you have a coefficient for 2 so you have to find what 2 to the power of 2 is =4 so then you have your new problem 4x+5=13 next you need to get 4x by itself so

-5 -5

then you have 4x=8. you divide by 4 on both sides

4. 4

so then you get x=2

2.So same here find what 3 to the power of 2 is =9

New equation 4x-1=9x+4x-4. Then combine like terms on the right you cant do it on the left because that is a separate part and those dont merge like terms so

9x+4x = 13x

new equation. 4x-1=13x-4

next subtract 4x on both sides

13x-4x=9x

new equation. -1=9x-4

next add 4 to both sides

-1+4= 3

new equation. 3=9x

so then divide 9 on both sides

3÷9= 0.33

x= 0.33

Hope this made sense and helps

7 0
3 years ago
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