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3 years ago

Please help me I will give brainliest!

Mathematics

2 answers:

jarptica [38.1K]3 years ago

7 0

Answer:

The answer is- D

Step-by-step explanation:

I took the test and got it right!

Hope this helps you

Viktor [21]3 years ago

4 0

Answer:

D. 2 3/4 + (-3 1/4) = -1 2/4

Step-by-step explanation:

Its like addition, but it is actually subtraction.

like this: 2 3/4 - 3 1/4 = -1 2/4

Hope this helps!

It you like it, plz mark me as brainiest!

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EASY BRAINLEST! ONLY TWO QUESTIONS I NEED HELP ASAP!!

mash [69]

Step-by-step explanation:

When you multiply both sides by a negative value you make the side that is greater have a "bigger" negative number, which actually means it is now less than the other side! This is why you must flip the sign whenever you multiply by a negative number.

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4 years ago

Casey wants to buy some instruments for his niece and nephew. He has $40 to spend. Based on the prices listed below, what is the

Maksim231197 [3]

$37 because when uu add the tambourine and xylophone uu get $37.45 but we have to round to the nearest dollar and the nearest dollar is 7 and the number next to it is not 5 or higher so we turn it to 0’s and uu get $37 .

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3 years ago

Solve this equation (2.2)(4.5)(0.6)

mote1985 [20]

Your answer would be 5.94.

4 0

3 years ago

The midpoint of AB is M(-1, –4). If the coordinates of A are (-3, -7), what are

quester [9]

Answer:

Step-by-step explanation:

If M(-1, 4) is midpoint of AB then:

$x_M-x_A=x_B - x_M\qquad\quad\ \wedge\qquad y_M-y_A=y_B - y_M\\\\ -1-(-3)=x_B-(-1)\qquad\wedge\qquad -4-(-7)=y_B -(-4)\\\\ -1+3=x_B+1\qquad\qquad\wedge\qquad\ \ -4+7=y_B+4 \\\\ {}\qquad x_B=1\qquad\qquad\wedge\qquad\qquad \ y_B=-1$

5 0

3 years ago

Find the limit, if it exists. (if an answer does not exist, enter dne.) lim (x, y) → (0, 0) x4 − 20y2 x2 + 10y2

Firdavs [7]

Traveling along the x-axis, we have

$\displaystyle\lim_{(x,y)\to(0,0)}\frac{x^4-20y^2}{x^2+10y^2}=\lim_{x\to0}\frac{x^4}{x^2}=\lim_{x\to0}x^2=0$

On the other hand, along the y-axis we get

$\displaystyle\lim_{(x,y)\to(0,0)}\frac{x^4-20y^2}{x^2+10y^2}=\lim_{y\to0}\frac{-20y^2}{10y^2}=\lim_{y\to0}(-2)=-2$

Therefore the limit doesn't exist.

5 0

3 years ago