Answer:
- trail mix: $1.25
- jelly beans: $3.50 per pound
Step-by-step explanation:
The difference between double the first purchase and the second purchase is $7 and 2 pounds of jelly beans. Hence a pound of jelly beans is $3.50.
(4t +8j) -2(2t +3j) = (33) -2(13) . . . . . let t and j represent pounds of trail mix and jelly beans, respectively
2j = 7 . . . . . . . . . . simplify
j = 7/2 = 3.50
Using that value in the first purchase, we get ...
2t +3(3.50) = 13
2t = 13 -10.50
t = 2.50/2 = 1.25
A pound of trail mix is $1.25.
Answer:
AB + BC = AC
BC = AC - AB
5x + 6 = 37 - (2 x + 3) = 37 -2 x - 3 = 34 - 2 x
7 x = 34 - 6 = 28
x = 4
BC = 5 x + 6 = 5 * 4 + 6 = 26
Check:
AB = 2 x + 3 = 2 * 4 + 3 = 11
AB + BC = 26 + 11 = 37
No, her current average is 225. She would need to score 350 points to get a 250.
Answer:
Segment Addition Postulate
Step-by-step explanation:
In geometry, the Segment Addition Postulate states that given 2 points A and C(in this case S and O), a third point B(in this case R) lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.
Meaning for R to lie on the line SO;
SR + RO must be equal to SO
if the sphere has a diameter of 5, then its radius is half that, or 2.5.
![\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=2.5 \end{cases}\implies V=\cfrac{4\pi (2.5)^3}{3}\implies V=\cfrac{62.5\pi }{3} \\\\\\ V\approx 65.44984694978736\implies V=\stackrel{\textit{rounded up}}{65.45}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20sphere%7D%5C%5C%5C%5C%20V%3D%5Ccfrac%7B4%5Cpi%20r%5E3%7D%7B3%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D2.5%20%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Ccfrac%7B4%5Cpi%20%282.5%29%5E3%7D%7B3%7D%5Cimplies%20V%3D%5Ccfrac%7B62.5%5Cpi%20%7D%7B3%7D%20%5C%5C%5C%5C%5C%5C%20V%5Capprox%2065.44984694978736%5Cimplies%20V%3D%5Cstackrel%7B%5Ctextit%7Brounded%20up%7D%7D%7B65.45%7D)
