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3 years ago

Which equation represents a line that passes through (2, - 1/2) and has a slope of 4 ?

Mathematics

1 answer:

solmaris [256]3 years ago

7 0

Answer:

y=4x-8.5

Step-by-step explanation:

Use point- slope form, since you are given one point and one slope.

y-y₁=m(x-x₁)

Plug coordinates and slope in.

y-(-1/2)=4(x-2)

Solve

y+1/2=4x-8

y=4x-8.5

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Makovka662 [10]

Let $u=x^2-4$ and $v=4x-5$ . By the product rule,

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}$

By the power rule, we have $(u^5)'=5u^4$ and $(v^4)'=4v^3$ , but $u,v$ are functions of $x$ , so we also need to apply the chain rule:

$\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}$

$\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}$

and we have

$\dfrac{\mathrm du}{\mathrm dx}=2x$

$\dfrac{\mathrm dv}{\mathrm dx}=4$

So we end up with

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3$

Replace $u,v$ to get everything in terms of $x$ :

$\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3$

We can simplify this by factoring:

$10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)$

$=2(x^2-4)^4(4x-5)^3(28x^2-57)$

7 0

3 years ago

The complementary angle of 45

Licemer1 [7]

Answer:

45°

Step-by-step explanation:

Complementary angles sum to 90°, thus

90° - 45° = 45° ← is the complement of 45°

4 0

3 years ago

Dr. Tu must administer emergency medicine to his patient, Mrs. Jones. The

galben [10]

Answer:

168

Step-by-step explanation: You would do 140/100 = 1.4 then multiply 120 by 1.4 which is 168.

3 0

3 years ago

Which sets of values belong to the domain of range of a relation?

aliina [53]

Domain is all X values, and range is the Y values.

5 0

3 years ago

Read 2 more answers

To graph ( 0, 15 ) what is the only direction you will move

Dominik [7]

Answer:

you will only move 15 units up

Step-by-step explanation:

since the y is the only one that has a value, then you will have to focus more on the direction where the y will go. and since the y's value is positive then you will have to go upwards.

3 0

3 years ago