<span>a1= (which is the first term.)
to find the 2nd term you plug in 2 for (an) in the formula given to you. =-4(2-1)^2 *remember an represents the term u are looking for *
now you start to solve it
-4(2-1)^2
-4 (1)^2
.
-4^2
= 16
so your first two terms are 2 and 16 .</span>
Answer:
Option B is right
Step-by-step explanation:
P(A or B)
In set theory if A and B are two sets we have either A occurs or B occurs or both as
P(A or B) = P(AUB)
This implies that A occurs or B occurs
Probability is calculated as P(A)+P(B)-P(AB)
P(AB) here represents both occurring and this is subtracted as this was added two times
Option A is wrong because this is AB
Option C is wrong because it is not necessary A occurs first
D is wrong because this is A'UB' where A' represents the complement of A
So correct answer out of four options is
B. the probability that in a single trial, event A occurs, event B occurs, or they both occur.
Answer:
First Integer = n = 45
Second Integer = n+1 = 45 + 1 = 46
And Third Integer = n+ 2 = 45 +2 = 47
Step-by-step explanation:
Let First integer = n
Second Integer = n+1
Third Integer = n+2
According to the question given (If the first of three consecutive integers is subtracted from 138, the result is the sum of the second and third) the equation will be:
138 - n = (n+1) + (n+2)
Solving the equation:
138 - n = n+1+n+2
138 - n = 2n+3
138 - 3 =2n +n
135 = 3n
135/3 = n
=> n= 45
So, First Integer = n = 45
Second Integer = n+1 = 45 + 1 = 46
And Third Integer = n+ 2 = 45 +2 = 47
