since the numerator is x² + 5x - 3, and therefore has a degree of 2, whilst the denominator, 4x¹ - 1, has a degree of 1, therefore, there's no horizontal asymptote.
recall, we only get a horizontal asymptote if the denominator's expression degree is equals or greater than that of the numerator's.
1+4(2x - 3)-x
Mutiply the bracket by 4
1+ (4)(2x)(4)(-3)-x
1+8x-12-x
8x-x+1-12 just rearranging
7x-11
Answer : D. 7x - 11
I am assuming the expression is (2x-3)(x+5) or (2x-3)(x-5). I will teach you how to solve for both as I am not sure which one you are asking for. There are 4 steps to multiplying.
1) Multiply the x times the second x
2) Multiply x times the second number
3) Multiply the number by the second x
4) Multiply the number by the second number.
(2x*x)+(2x*5)+(-3*x)+(-3*5)=(2

)+(10x)+(-3x)+(-15)=2

+7x-15
(2x*x)+(2x*-5)+(-3*x)+(-3*-5)=(2

)+(-10x)+(-3x)+(15)=2

-13x+15
Your answer is 2

+7x-15 or 2

-13x+15. Does that answer your question?