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3 years ago

Find the volume of the cylinder A-16990 B-8491 C-4247 D-2369

Mathematics

1 answer:

defon3 years ago

4 0

Answer:

V = 8491 mm^3

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2 h

We know the radius is 13 and the height is 16

V = pi * (13)^2 *16

V = 169*16 *pi

V =2704 *pi

Let pi be approximated by 3.14

V =2704(3.14)

V =8490.56

To the nearest whole number

V = 8491 mm^3

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suppose Q is the midpoint of PR. use the information to find the missing value. PQ equals 3x + 14 and QR equals 7X - 10; find X.

NARA [144]

Answer:

x=6

Step-by-step explanation:

A midpoint is the middle point of a line segment, therefore it is equal distances from both ends of the segment.

This means that PQ and QR have the same length. So all we have to do is set each value equal to each other, and then solve for X.

$3x+14=7x-10\\3x+24=7x\\24-4x\\x=6$

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3 years ago

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Write thThe bookstore is selling a series of 4 books for $97.50. What is the unit price for one book? Round your answer to the n

Sveta_85 [38]

Answer: $24.47

Step-by-step explanation: I don’t understand the kilometers.

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3 years ago

Firewood can be sold in cords. the wood is cut into equal lengths and stacked evenly in a rack. which geometric shape can be use

Nadya [2.5K]

To estimate the volume of the chord of wood, since the wood exists cut into equal lengths and stacked evenly in a rack then we can use a cylinder as a model.

<h3>What is a cylinder?</h3>

In mathematics, a cylinder exists as a three-dimensional solid that holds two parallel bases joined by a curved surface, at a fixed distance. These bases exist normally circular (like a circle) and the center of the two bases exists joined by a line segment, which exists named the axis.

A cylinder exists as a closed solid that contains two parallel circular bases joined by a curved surface.

To calculate the volume of the chord of wood, since the wood exists cut into equal lengths and stacked evenly in a rack then we can use a cylinder as a model.

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2 years ago

Circle B has a center at point (0, 2) and a point W on the circle at (3, 3). Which equation represents a line that is tangent to

Solnce55 [7]

According to the given information, the equation represents a line that is tangent to the circle and goes through the point W is given by:

y = -x + 6.

<h3>What is the equation of the circle?</h3>

The equation of a circle of center $(x_0,y_0)$ and radius r is given by:

$(x - x_0)^2 + (y - y_0)^2 = r^2$

In this problem, we have that the center is at point (0,2), hence:

$x^2 + (y - 2)^2 = r^2$

It goes through point (3,3), hence:

$3^2 + (3 - 2)^2 = r^2$

$r^2 = 10$

Hence, the equation is:

$x^2 + (y - 2)^2 = 10$

<h3>What is the equation of the tangent line at point W?</h3>

It is given by:

$y - y(0) = \frac{dy}{dx}|_{W}(x - x(0))$

Applying implicit differentiation, we have that:

$2x + 2y\frac{dy}{dy} = 0$

$\frac{dy}{dx} = -\frac{x}{y}$

Point W(3,3), hence:

$(x_0, y_0) = (3,3)$

$\frac{dy}{dx} = -\frac{3}{3} = -1$

Hence the equation is:

y - 3 = -(x - 3).

y = -x + 6.

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2 years ago

A personnel manager is concerned about absenteeism. She decides to sample employee records to determine if absenteeism is distri

nlexa [21]

Answer:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

For this case we want to test:

H0: Absenteeism is distributed evenly throughout the week

H1: Absenteeism is NOT distributed evenly throughout the week

We have the following data:

Monday Tuesday Wednesday Thursday Friday Saturday Total

12 9 11 10 9 9 60

The level of significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{60}{6}= 10$ and the expected value is the same for all the days since that's what we want to test.

now we can calculate the statistic:

$\chi^2 = \frac{(12-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(11-10)^2}{10}+\frac{(10-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(9-10)^2}{10}=0.8$

Now we can calculate the degrees of freedom (We know that we have 6 categories since we have information for 6 different days) for the statistic given by:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

4 0

3 years ago