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kaheart [24]
3 years ago
11

How to solve this with solution

Mathematics
1 answer:
mojhsa [17]3 years ago
7 0

Step-by-step explanation:

nasa picture po yunv sagot

#HOPE IT HELPS

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What's the answer to question 10 and 11
Vera_Pavlovna [14]
Question 10: 5.723 < 5.724 < 5.725
Question 11: I'm guessing it will be 6, since the other part is cut off

hope this helps
3 0
3 years ago
What expression is equivalent to 7(3x-2) + 4(x+5)
Dmitry [639]
7(3x-2)+4(x+5)
= 7*(3x)-7*2+4x+4*5 (distributive property)
= 21x -14 +4x +20
= 25x +6

Final answer: 25x+6.

Hope this helps~
5 0
3 years ago
Read 2 more answers
HELP DUE AT 11:59!!!!!
faltersainse [42]

Answer:

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5 0
3 years ago
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3/z when z=2 SORRY FOR HAVING 2 QUESTIONS IN A ROW
8090 [49]

3/z when z = 2

= 3/2

= 1.5

This is the answer

4 0
3 years ago
Read 2 more answers
For what values of $j$ does the equation $(2x+7)(x-5) = -43 + jx$ have exactly one real solution? express your answer as a list
LiRa [457]

The values of 'j' are -11,5.

What is a Quadratic Equation?

  • Quadratic equations are the polynomial equations of degree 2 in one variable of the type f(x) = ax^{2} + bx + c = 0 where a, b, c, ∈ R and a ≠ 0.
  • The standard form of a quadratic equation is ax^{2} + bx + c = 0 .

Here, the given equation is (2x+7)(x-5) = - 43 + jx

On simplifying the equation we get,

2x^{2} -10x+7x-35=-43+jx\\2x^{2} -3x-35+43-jx=0\\2x^{2} -3x-jx+8=0\\2x^{2} -(3+j)x+8=0.....(1)\\

By comparing the given equation with the standard form of the quadratic equation we get,

a = 2

b = - (3 + j)

c = 8

Therefore,

(-(3+j))^{2} -4\times2\times8=0\\(3+j)^{2} -64=0\\(3+j)^{2} =64\\

Take the square root of both sides,

\sqrt{(3+j)^{2} }=\sqrt{64} \\

3 + j = ±8

Therefore,

3 + j = 8

j = 8 - 3        

j = 5

or

3 + j = -8

j = -8 - 3

j = -11

Hence, the possible values of 'j' are -11,5.

Learn more about the quadratic equation at brainly.com/question/8649555

#SPJ4

4 0
2 years ago
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