Answer:
170 children
74 students
85 adults
Step-by-step explanation:
Given
Let:
For the capacity, we have:
For the tickets sold, we have:
Half as many as adults are children implies that:
Required
Solve for A, C and S
The equations to solve are:
-- (1)
-- (2)
-- (3)
Make C the subject in (3)
Substitute in (1) and (2)
-- (1)
Make S the subject
-- (2)
Substitute
Solve for A
Recall that:
Recall that:
Hence, the result is:
Answer: -1 < x < 1
Step-by-step explanation: Solve for x.
Graph line is down below!
Hope this helps you out! ☺
-Leif-
Don't touch the center. It is already even.
Start anywhere by connecting a dotted line from one vertex to the next. To keep things so we know what we are talking about, go clockwise. Now you have 2 points that are Eulerized that were not before.
Skip and edge and do the same thing to the next two vertices. Those two become eulerized. Skip an edge and do the last 2.
Let's try to describe this better. Start at any vertex and number them 1 to 6 clockwise.
Join 1 to 2
Join 3 to 4
Join 5 to 6
I think 3 is the minimum.
3 <<<< answer
90 points where at least two of the circles intersect.
<h3>Define circle.</h3>
A circle is a closed, two-dimensional object where every point in the plane is equally spaced from a central point. The line of reflection symmetry is formed by all lines that traverse the circle. Additionally, every angle has rotational symmetry around the centre.
Given,
Four distinct circles are drawn in a plane.
Start with two circles; they can only come together in two places. The third circle contacts each of the previous two circles in two spots each, bringing the total number of intersections up to four with the addition of a third circle. The total number of intersections will rise by another 6 when a fourth circle intersects the first three. And the list goes on.
As a result, we get a recognizable, regular pattern: for each additional circle, there are two more intersections overall than in the circle before it.
The total number of intersections can be expressed as the sum because the maximum number of intersections of 10 circles must occur when each circle contacts every other circle in 2 places each.
2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18 = 90.
90 points where at least two of the circles intersect.
To learn more about circle, visit:
brainly.com/question/11213974
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