Answer:
$14.80(m) + $12(n) = $95.2
Solved:
$14.80(4) + $12(3) = $95.2
Step-by-step explanation:
m represents Adults ($14.80m) | n represents Children ($12n)
4 Adults times $14.80 equals $59.2
3 Children times $12 equals $36
Add $36 and $59.2 and you get $95.2
1] Given that the value of x has been modeled by f(x)=12500(0.87)^x, then:
the rate of change between years 1 and 5 will be:
rate of change is given by:
[f(b)-f(a)]/(b-a)
thus:
f(1)=12500(0.87)^1=10875
f(5)=12500(0.87)^5=6230.3
rate of change will be:
(6230.3-10875)/(5-1)
=-1161.2
rate of change in years 11 to 15 will be:
f(11)=12500(0.87)^11=2701.6
f(15)=12500(0.87)^15=1,547.74
thus the rate of change will be:
(1547.74-2701.6)/(15-11)
=-288
dividing the two rates of change we get:
-288/-1161.2
-=1/4
comparing the two rate of change we conclude that:
The average rate of change between years 11 and 15 is about 1/4 the rate between years 1 and 5.
The answer is D]
2] Given that the population of beavers decreases exponentially at the rate of 7.5% per year, the monthly rate will be:
monthly rate=(n/12)
where n is the number of months
=7.5/12
=0.625
This is approximately equal to 0.65%. The correct answer is A. 0.65%
Add up minutes
1stmonth+2ndmonth+3rdmonth=320+243+489=1052
how many 200's are there
6 of them (companies want money so they see, ok, you bought like 1 minute, we will charge you for the whole 200 minutes since you got in that zone)
6 times 25=150
cost is $150 (mom is not going to be happy, she spend like 3% of her waking hours takling on the phone)
Firstly, given this information there could be 25 labradors and poodles and only 4 boxers and 1 spaniel. However, assuming that there are only boxers and spaniels at the dog show the first thing to do is to divide 30 by 5 = 6 so the answer is, There are 6 spaniels.
