d=-8 is the answer for first eqn
cost of one peppermint cookies = $ 0.6
cost of one cinnamon sugar cookies = $ 0.3
<h3><u>Solution:</u></h3>
Let "p" be the cost of one peppermint cookies
Let "c" be the cost of one cinnamon sugar cookies
<u><em>To find: cost of each cookie</em></u>
<h3><u><em>
On the first day, they sold 120 peppermint cookies and 30 cinnamon sugar cookies for a total of $81</em></u></h3>
We can frame a equation as:
120 peppermint cookies x cost of one peppermint cookies + 30 cinnamon sugar cookies x cost of one cinnamon sugar cookies = $ 81

120p + 30c = 81 --------- eqn 1
<h3><u><em>
The next day they made $60 by selling 70 peppermint cookies and 60 cinnamon sugar cookies</em></u></h3>
70 peppermint cookies x cost of one peppermint cookies + 60 cinnamon sugar cookies x cost of one cinnamon sugar cookies = $ 60

70p + 60c = 60 --------- eqn 2
Let us solve eqn 1 and eqn 2 to find values of "p" and "c"
Multiply eqn 1 by 2
240p + 60c = 162 --- eqn 3
Subtract eqn 2 from eqn 3
240p + 60c = 162
70p + 60c = 60
(-) -------------------------
170p = 102
<h3>p = 0.6</h3>
Substitute p = 0.6 in eqn 1
120p + 30c = 81
120(0.6) + 30c = 81
72 + 30c = 81
30c = 9
<h3>c = 0.3</h3>
<u><em>Summarizing the results:</em></u>
<em>cost of one peppermint cookies = $ 0.6</em>
<em>cost of one cinnamon sugar cookies = $ 0.3</em>
Answer:
3685.7%
Step-by-step explanation:
Please don't get mad if it's wrong.
Y=mx+b // standard form
3x=12-2y
2y=-3x+12
y=-3/2x+12/2
y=-3/2x+6
So the answer is: y = -3/2x+6
Answer:
The penquins had more fish.
Number of fish polar bears and penguins had combined is 5,520.
Step-by-step explanation:
The polar bears had 2,208 fish (48 piles times 46 fish).
The penquins had 3,312 fish (144 piles [48 times 3] times 23 fish [46 divided by 2]).
2208 fish plus 3312 fish equals 5,520 fish.