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Oksana_A [137]
2 years ago
11

Help me out please !!!!

Mathematics
1 answer:
Nikolay [14]2 years ago
6 0

Answer:

B) 6<x<90

Step-by-step explanation:

48+42=90

48-42=6

There will be a number greater than and a number less than x.

90>6

6<x<90

Hope this helps :)

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How do I find the domain n range of this graph​
motikmotik

Domain = {-3, 2}

Range = All real numbers

We can represent the range in interval notation as (-\infty, \infty) which is basically saying -\infty < y < \infty. The range is all real numbers due to the arrows meaning the graph extends up and down forever. So any y value is possible.

Notice with the domain we only have 2 valid x values -3 and 2. No other x values are allowed. Normally we use an interval of some kind to set up the domain, but we only have a set of values instead. The curly braces indicate "set".

7 0
3 years ago
My monthly cell phone bill is $40 plus $.10 for each text message. Write an equation to show the cost of texting. What is my tot
Otrada [13]

Answer:

y=.1x+40; Your total monthly bill is $48 for 80 text messages.

Step-by-step explanation:

y is your total bill

x represents each text message

40 is you cellphone bill cost

.1 is the cost per text message

(y=.1x+40 becomes your equation)

plug 80 to represent "x"

y=.1*80+40 --->  y=48

your total monthly bill is $48

8 0
2 years ago
A 140-meter rope is cut into two pieces. One piece is four times as long as the other. How long is each piece?
grandymaker [24]

Answer:

28meters and 112meters

Step-by-step explanation:

one piece is x

the other is 4x

therefore; 4x+x=140

5x= 140

divide both sides by 5

x=28

4x=4(28)

=112

3 0
2 years ago
The sum of two numbers is odd. Can the quotient of the two numbers be an odd number?
Natalka [10]

Answer: No.

Step-by-step explanation:

I guess that here we have the statement:

If the sum of two numbers is odd----> can their quotient be an odd number?

first, for n an integer number, we have that:

an odd number can be written as 2n + 1

an even number can be written as 2n.

The sum of two numbers is only odd if one of them is odd and the other even.

Then we have a number that is 2n and other that is 2k + 1, for n and k integer numbers.

Now, let's see if the quotient can also be an odd number.

One way to think this is:

There is an odd number such that when we multiply it by another odd number, the result is an even number?

no, and i can prove it as:

let 2k + 1 be an odd number, and 2j + 1 other.

the product is:

(2k + 1)*(2j + 1) = 2*(2*k*j + k + j) + 1

and as k and j are integers, also does 2*k*j + k + j, so:

2*(2*k*j + k + j) + 1 is an odd number.

This says that the product of two odd numbers is always odd, then we never can have that the quotient between an even number and an odd number is odd.

4 0
3 years ago
Solve for x... Please i need help!
Strike441 [17]

Answer:

6

Step-by-step explanation:

x=6

ax+bx=cx

10+bx=16

10+6=16

x=6

3 0
3 years ago
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