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Brums [2.3K]
3 years ago
13

15 points please help thank you

Mathematics
1 answer:
Likurg_2 [28]3 years ago
5 0

Answer:

  1.8

Step-by-step explanation:

The point of intersection of the left-side function with the right-side function is the value of x where the two functions evaluate to the same quantity. That value of x is near 1.785, as indicated on the attached graph. Rounded to the nearest tenth, the value of x is 1.8.

_____

<em>Refinement of the graphical solution</em>

An iteration method called Newton's Method can be used to refine the estimate to the limit of accuracy of the calculator. For that, it is convenient to define a function such as the one you get when you subtract the right side from the left side. Newton's Method is good at finding the zero(s) of such a function.

The function defined as g(x) in the attachment is the iterator for Newton's Method. It gives the next "guess" based on the guess you give it as an argument. When there is no change, the guess is as accurate as the calculator can provide. Here, that refined estimate of x is x ≈ 1.78522264685.

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Using linked lists or a resizing array; develop a weighted quick-union implementation that removes the restriction on needing th
balu736 [363]

Answer:

Step-by-step explanation:

package net.qiguang.algorithms.C1_Fundamentals.S5_CaseStudyUnionFind;

import java.util.Random;

/**

* 1.5.20 Dynamic growth.

* Using linked lists or a resizing array, develop a weighted quick-union implementation that

* removes the restriction on needing the number of objects ahead of time. Add a method newSite()

* to the API, which returns an int identifier

*/

public class Exercise_1_5_20 {

public static class WeightedQuickUnionUF {

private int[] parent; // parent[i] = parent of i

private int[] size; // size[i] = number of sites in subtree rooted at i

private int count; // number of components

int N; // number of items

public WeightedQuickUnionUF() {

N = 0;

count = 0;

parent = new int[4];

size = new int[4];

}

private void resize(int n) {

int[] parentCopy = new int[n];

int[] sizeCopy = new int[n];

for (int i = 0; i < count; i++) {

parentCopy[i] = parent[i];

sizeCopy[i] = size[i];

}

parent = parentCopy;

size = sizeCopy;

}

public int newSite() {

N++;

if (N == parent.length) resize(N * 2);

parent[N - 1] = N - 1;

size[N - 1] = 1;

return N - 1;

}

public int count() {

return count;

}

public int find(int p) {

// Now with path compression

validate(p);

int root = p;

while (root != parent[root]) {

root = parent[root];

}

while (p != root) {

int next = parent[p];

parent[p] = root;

p = next;

}

return p;

}

// validate that p is a valid index

private void validate(int p) {

if (p < 0 || p >= N) {

throw new IndexOutOfBoundsException("index " + p + " is not between 0 and " + (N - 1));

}

}

public boolean connected(int p, int q) {

return find(p) == find(q);

}

public void union(int p, int q) {

int rootP = find(p);

int rootQ = find(q);

if (rootP == rootQ) {

return;

}

// make smaller root point to larger one

if (size[rootP] < size[rootQ]) {

parent[rootP] = rootQ;

size[rootQ] += size[rootP];

} else {

parent[rootQ] = rootP;

size[rootP] += size[rootQ];

}

count--;

}

}

public static void main(String[] args) {

WeightedQuickUnionUF uf = new WeightedQuickUnionUF();

Random r = new Random();

for (int i = 0; i < 20; i++) {

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int q = r.nextInt(i+1);

if (uf.connected(p, q)) continue;

uf.union(p, q);

System.out.printf("%5d-%d", p, q);

uf.union(r.nextInt(i+1), r.nextInt(i+1));

}

}

}

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3 years ago
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Answer:

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Step-by-step explanation:

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5 0
3 years ago
FAST YOU ANSWER FIRST YOU GET FREE BRAINLIEST
11111nata11111 [884]
-10v^9+8v^6+2v^5

10=5*2
8=2^3
2=2

The common factor is 2 and its least exponent is 1
The least exponent for the variable v is 5

Then, the GFC of the polynomial is 2v^5

Factoring:
2v^5 [ -(10v^9)/(2v^5)+(8v^6)/(2v^5)+(2v^5)/(2v^5) ] =
2v^5 (-5v^(9-5)+4v^(6-5)+1) =
2v^5 (-5v^4+4v+1)
8 0
3 years ago
Read 2 more answers
Why is #2 the expression ln(2e)^3x equivalent to choice B?
motikmotik
Hello:
ln(2e^3x) =ln2+lne^3x
<span>                =ln2 +3xlne
                 = ln2+3x        .....lne=1       
               </span><span>choice B</span>
8 0
3 years ago
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