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3 years ago

What set of reflections would carry triangle abc onto itself?

2 answers:

7 0

Since all reflections are inverse of itself, carrying any reflection about the same axis twice will carry the preimage back to itself.

shepuryov [24]3 years ago

3 0

Answer is y axis , x axis, y axis , x axis .

Let The triangle ABC is in first quadrant of a two dimensional graph where it is reflected by positive of y axis and it is reflected image will be in second quadrant ,there it is reflected by negative of x axis and the reflected image will be in third quadrant now, here it is reflected by negative of y axis and its reflected image will be in fourth quadrant ,finally it will reflected by positive of x axis and its reflected image will be back in first quadrant.

So the answer is y axis , x axis, y axis , x axis are the of reflections which would carry triangle onto itself.

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For each level of precision, find the required sample size to estimate the mean starting salary for a new CPA with 95 percent co

Rzqust [24]

Answer:

(a) Margin of error ( E) = $2,000 , n = 54

(b) Margin of error ( E) = $1,000 , n = 216

(c) Margin of error ( E) = $500 , n= 864

Step-by-step explanation:

Given -

Standard deviation $\sigma$ = $7,500

$\alpha$ = 1 - confidence interval = 1 - .95 = .05

$Z_{\frac{\alpha}{2}}$ = $Z_{\frac{.05}{2}}$ = 1.96

let sample size is n

(a) Margin of error ( E) = $2,000

Margin of error ( E) = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

E = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$E^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{2000^{2}} \times 7500^{2}$

n = 54.0225

n = 54 ( approximately)

(b) Margin of error ( E) = $1,000

E = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

1000 = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$1000^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{1000^{2}} \times 7500^{2}$

n = 216

E = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

500 = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$500^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{500^{2}} \times 7500^{2}$

n = 864

7 0

3 years ago

X(4-k)=p solve for k

den301095 [7]

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3 years ago

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I need help thank you

Anni [7]

Answer:

Step-by-step explanation:

Because when you are doing a reflection, You sort of see if you can fold it and it will still be the same. If you put the first triangle on the second one, they have the same shape.

Hope this helps :)

5 0

3 years ago

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Write 10 9 as a decimal. Round to the nearest thousandth if necessary.

svet-max [94.6K]

Answer:

If you mean 10/9 then the answer should be 1.1 repeating itself

Step-by-step explanation:

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2 years ago

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