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emmainna [20.7K]
3 years ago
9

Plz Help!!! Fast!!

Mathematics
2 answers:
Allisa [31]3 years ago
6 0

Answer:

if the gold in this ratio is the 2 out of the 2:5 then the answer is 56 but if its the 5 then its 350

Step-by-step explanation:

zmey [24]3 years ago
5 0

The weight of gold is 56

Step-by-step explanation:

gold= 2

sliver = 5

weight of gold = x

weight of silver = 140

2/5 = x/140 solve for x

280=5x

x=280/5

x= 56

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In health class, students record the weights of the sandwiches they have for lunch. The weights are shown in the line plot below
Dvinal [7]
To find the average weight, you need to add all of the numbers and then divide them
I'll start off by doing this:
1/8+1/8 = 2/8
1/4+1/4+1/4+1/4 = 1
3/8+3/8 = 6/8
1/2+1/2 = 1
then I'll add them together:
2/8+6/8 = 1
1 + 1 + 1 =3
now we need to divide the amount of numbers. the amount of sandwiches weighted (10) will have to be divided
therefore, we get 3/10. because this can't be simplified, this will be your final answer.
4 0
3 years ago
Please write out the problem on paper
skad [1K]
Your answer will be n5
7 0
3 years ago
I'd appreciate the help, its making my brain hurt plus i never was good at algebra
Andrei [34K]

Answer: I got -2

I plugged -6 in for y and then simplified. -6 x -6 = 36. 7 x -6 = -42. So 36 - 42 = -6. -6 + 4 = -2

3 0
3 years ago
In a study of the effect of college student employment on academic performance, the following summary statistics for GPA were re
11Alexandr11 [23.1K]

Answer:

Step-by-step explanation:

This is a test of 2 independent groups. The population standard deviations are not known. Let μemployed(μ1) be the sample mean of students who are employed and μnot employed(μ2) be the sample mean of students who are not employed

The random variable is μ1 - μ2 = difference in the mean of the employed and unemployed students.

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 < μ2 H1 : μ1 - μ2 < 0

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(μ1 - μ2)/√(s1²/n1 + s2²/n2)

From the information given,

μ1 = 3.22

μ2 = 3.33

s1 = 0.475

s2 = 0.524

n1 = 172

n2 = 116

t = (3.22 - 3.33)/√(0.475²/172 + 0.524²/116)

t = - 1.81

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [0.475²/172 + 0.524²/116]²/[(1/172 - 1)(0.475²/172)² + (1/116 - 1)(0.524²/116)²] = 0.00001353363/0.00000005878

df = 230

We would determine the probability value from the t test calculator. It becomes

p value = 0.036

Since alpha, 0.05 > than the p value, 0.036, then we would reject the null hypothesis.

Therefore, at a 5% significant level, this information support the hypothesis that for students at this university, those who are not employed have a higher mean GPA than those who are employed

3 0
3 years ago
How to convert angle in radians to degrees?
jek_recluse [69]
360° = 2π
2 = 360° / π
1 rad = 360° / 2π
3 0
3 years ago
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